The question is missing the graph. So, the graph is attached below.
Answer:
The value of
is 7380 N.
Explanation:
Given:
Mass of the ball is, 
Initial velocity of the ball is, 
Final velocity of the ball is, 
From the graph,
Time interval for which the force acts, 
Height of the triangle is equal to the maximum force acting on the ball = 
Now, we know that, impulse acting on the ball is equal to the area under the curve of force and time graph.
So, impulse is equal to the area of the triangle and is given as:
Impulse = 
Here, base is time interval
and height is
.
Impulse = 
Impulse = 
Now, we also know that, impulse is equal to the change in momentum of a body.
Therefore, change in momentum (Δp) is given as:

Now, change in momentum is equal to impulse acting on the ball. Thus,

Therefore, the value of
is 7380 N.