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ipn [44]
2 years ago
11

Can someone help me?

Physics
1 answer:
Setler [38]2 years ago
4 0

Answer: (1, 30), (2,10), (3,40), (4,20)

Explanation:

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A lightweight string is wrapped several times around the rim of a small hoop. If the free end of the string is held in place and
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Answer:

Explanation:

Let T be the tension

For linear motion of hoop downwards

mg -T = ma , m is mass of the hoop . a is linear acceleration of CG of hoop .

For rotational motion of hoop

Torque by tension

T x R ,      R is radius of hoop.

Angular acceleration be α,

Linear acceleration a = α R

So TR = I  α

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a = TR² / I

Putting this value in earlier relation

mg -T = m TR² / I

mg = T ( 1 + m R² / I )

T = mg / ( 1 + m R² / I )

mg / ( 1 + R² / k² )

Tension is less than mg or weight because denominator of the expression is more than 1.

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hope that helps?

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