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stich3 [128]
3 years ago
7

78. A particle moves along the x- axis. The velocity of the particle at time tis given by 4vt()=3 t +1 . If the position of the

particle is x=1when t=2, what is the position of the particle when t=4? (A) 0.617 (B) 0.647 (C) 1.353 (D) 5.713

Physics
1 answer:
RoseWind [281]3 years ago
3 0

Explanation:

Below is an attachment containing the solution

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What is the
Len [333]

Answer:

d=5\ g/cm^3

Explanation:

Given that,

Mass of the object, m = 100 grams

Volume of the object, V = 20 cm³

We need to find the density of the object. We know that, density is equal to mass per unit volume. So,

d=\dfrac{m}{V}\\\\d=\dfrac{100\ g}{20\ cm^3}\\\\d=5\ g/cm^3

So, the density of the object is equal to 5\ g/cm^3.

6 0
3 years ago
What is the acceleration of a softball if it has a mass of 0.5 kg and hits the cathers glove with a force of 25n
ioda
Acceleration is found if we have the force and mass. 

With the following equation: F = ma, we can find the missing values. 

F = 25n
M = 0.5 kg
a = ?

a = f/m
a = 25/0.5
a = 50

a = 50 m/s

So, the acceleration is 50 m/s^2 
3 0
3 years ago
If the ball that is thrown downward has an acceleration of magnitude aaa at the instant of its release (i.e., when there is no l
kakasveta [241]

Explanation:

At the instant of release there is no force but an acceleration of a, this means the ball is falling freely under the force of gravity. Then the acceleration would be due to force of gravity and acceleration a = g =9.81 m/s^2.

g= acceleration due to gravity

5 0
2 years ago
Two forces act on a moving object that has a mass of 27 kg. One has a magnitude of 12 N and points due south, while the other ha
levacccp [35]

0.77 m/s2 directed 35° south of west

net force = (-17,-12)

net force = mass * acceleration

(-17,-12) = 27 * (x-acceleration,y-acceleration)

(x-acceleration,y-acceleration) = (-17/27,-12/27) = (-0.629629629..., -0.444...)

angle of acceleration = tan^-1 (-0.444.../-0.629629...) = 35.21759 degrees below negative x-axis.

magnitude of acceleration = sqrt((-0.629629...)^2 + (-0.444...)^2) = 0.77069 (5dp)

7 0
2 years ago
Is a dog chasing its tail acceleration
AfilCa [17]

Answer:

if he is chasing his tail faster with each circle, then that would be acceleration, If not then no

7 0
2 years ago
Read 2 more answers
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