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stich3 [128]
3 years ago
7

78. A particle moves along the x- axis. The velocity of the particle at time tis given by 4vt()=3 t +1 . If the position of the

particle is x=1when t=2, what is the position of the particle when t=4? (A) 0.617 (B) 0.647 (C) 1.353 (D) 5.713

Physics
1 answer:
RoseWind [281]3 years ago
3 0

Explanation:

Below is an attachment containing the solution

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a particle is moving along a circular path having a radius of 4 in such that its position as a function of time is given by thet
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Answer:

Explanation:

Given

radius of circular path r=4\ in.

Position is given by

\theta =\cos 2t---1

Differentiate 1  to angular velocity we get

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a_t=-4\cos 2t\times 4=-16\cos 2t

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a_r=(-2\sin 2t)^2\cdot 4

a_r=16\sin^2(2t)

a_{net}=\sqrt{a_r^2+a_t^2}

a_{net}=\sqrt{(16\sin ^2(2t)+(-16\cos 2t)^2}

a_{net}=\sqrt{256\cos ^2(2t)+256\sin ^4(2t)}                                                    

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