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Blizzard [7]
3 years ago
15

The formula $F = \frac{9}{5} C + 32$ can be used to convert temperatures between degrees Fahrenheit ($F$) and degrees Celsius ($

C$). How many degrees are in the Celsius equivalent of $-22^\circ F$?
Physics
1 answer:
slamgirl [31]3 years ago
7 0

Answer:

-30° C

Explanation:

Data provided in the problem:

The formula for conversion as:

F  = (9/5)C + 32

Now,

for the values of F = -22 , C = ?

Substituting the value of F in the above formula, we get

-22 = (9/5)C + 32

or

-22 - 32 = (9/5)C

or

(9/5)C = - 54

or

C = - 54 × (5/9)

or

C = - 30 °

Hence, -22 Fahrenheit equals to -30°C

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mass of the sky diver is 03.4 kg. What are the magnitude and direction or acceleration A person pulls a hand-language for a dist
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Answer:

How much work is done if the same ...

Explanation:

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3 0
3 years ago
Before a collision, a 50.0-kg object is moving at +5.0 m/s. Find the impulse that acted on the object if, after the collision, i
Virty [35]

Answer:

<em>J=600 kg m/s </em>

Explanation:

<u>Impulse And Momentum </u>

Suppose a particle is moving at a certain speed v_1 and changes it to v_2. The impulse J is equivalent to the change of linear momentum. The momentum can be computed by

p=mv

The initial and final momentums are given, respectively, by:

p_1=mv_1,\ p_2=mv_2

Thus, the change of momentum is

\Delta p=p_2-p_1=m(v_2-v_1)

It's equal to the Impulse J

J=\Delta p

J=m(v_2-v_1)

Our data is

m=50\ kg,\ v_1=5\ m/s,\ v_2=17\ m/s

J=50\ (17-5)

J=600\ kg\ m/s

7 0
3 years ago
Yeah, so, my teacher finna kill me if I don't turn this in today..
AnnZ [28]

Answer:

Blank 1: 10

Blank 2: 4

Blank 3: 10

Blank 4: 5

Blank 5: 5

7 0
3 years ago
Unpolarized light of intensity I0 is incident on a series of three polarizing filters. The axis of the second filter is oriented
notka56 [123]

Answer:

The intensity of the light transmitted through the third filter is  I_3 = \frac{I_o}{8}

Explanation:

From the question we are told

   The intensity of the unpolarised light I_o

   The angle between the first and second polarizer is  \theta _1 = 45^o

     The angle between the first and third  polarizer is  \theta _2 = 90^o

   

Generally the intensity of light emerging from the first polarizer is mathematically represented as

           I_1 = \frac{I_o}{2}

According to Malus law the intensity of light emerging from the second polarizer is mathematically represented as

         I_2 = I_1 cos^2 (\theta_1)

Substituting for I_1 and \theta _1

          I_2 = \frac{I_o}{2}  cos^2 (45)

          I_2 = \frac{I_o}{4 }

According to Malus law the intensity of light emerging from the third polarizer is mathematically represented as

         I_3 = I_2 cos ^2 (\theta_2 - \theta_1)

Substituting for I_2 and \theta _1 \ and \  \theta _2

         I_3 = \frac{I_o}{4}  cos ^2 (90 - 45)

         I_3 = \frac{I_o}{8}

4 0
3 years ago
The front of a 1300 kg car is designed to absorb the shock of a collision by having a "crumple zone" in which the front 1.20 m o
Novay_Z [31]

Answer:

<em>The collision last 0.83 s</em>

Explanation:

Using the equation of motion,

S = (v+u)t/2 ........................ Equation 1

making t the subject of the equation,

t = 2S/(v+u)..................... Equation 2

Where S = distance, v = final velocity, u = initial velocity, t = time

Given: v = 0 m/s, u = 29.0 m/s, S = 1.20 m,

Substituting these values into equation 2

t = 2(1.2)/(29+0)

t = 2.4/29

t = 0.83 sec.

<em>Thus the collision last 0.83 s</em>

7 0
3 years ago
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