My calculations state, not rounding, the mass is 1.8
Answer:
a) 32.58 m/s²
b) 161.84 m/s
Explanation:
Initial velocity = u = 0
Final velocity = v = 145 m/s
Time taken = t = 4.45 s
s = Displacement of dragster = 402 m
a = Acceleration


The final velocity is greater than the velocity used to find the average acceleration due to the gear changes. The first gear in a dragster has the most amount of toque which means the acceleration will be maximum. The final gears have less torque which means the acceleration is lower here. The final gears have less acceleration but can spin faster which makes the dragster able to reach higher speeds but slowly.
Answer:
10.6cm
Explanation:
We are given 5.3cm below the starting point (spring extension).
Therefore, to find static vertical equilibrium, we use the equation:
kx = mg
Where:
k = spring constant =
=mg/5.3 kg/s²
We are told the object was dropped from rest.
Therefore:
loss in potential energy = gain in spring p.e
Let's use the expression:
mgx = ½kx²
We are asked to find the stretch at maximum elongation x.
To find x, we make x subject of the formula.
Therefore, we have:
x = 2mg/k (after rearranging the equation above)
x = (2mg) / (mg/5.3)
x = 10.6cm
Answer:
6.88 m/s
Explanation:
The Conservation of Energy states that:
Initial Kinetic Energy + Initial Potential Energy = Final Kinetic Energy + Final Potential Energy
So we can write

We can cancel the common factor of
which leaves us with

Lets solve for 

Subtract
from both sides of the equation.

Multiply both sides of the equation by 2.

Simplify the left side.
Apply the distributive property.

Cancel the common factor of 2.

Take the square root of both sides of the equation to eliminate the exponent on the right side.

We are given
.
We can now solve for the final velocity.

Anything multiplied by 0 is 0.


