Answer:
(A) Q = 321.1C (B) I = 42.8A
Explanation:
(a)Given I = 55A−(0.65A/s2)t²
I = dQ/dt
dQ = I×dt
To get an expression for Q we integrate with respect to t.
So Q = ∫I×dt =∫[55−(0.65)t²]dt
Q = [55t – 0.65/3×t³]
Q between t=0 and t= 7.5s
Q = [55×(7.5 – 0) – 0.65/3(7.5³– 0³)]
Q = 321.1C
(b) For a constant current I in the same time interval
I = Q/t = 321.1/7.5 = 42.8A.
Answer:
True
Explanation:
When an object is held higher, it has more potential energy because more energy is stored from its higher position to swing further than it would have, had it been held lower.
Answer:
0.00377143
Explanation:
You would have to divide to get the frequency.
1.32/350 = 0.00377143
I apologize if it is incorrect-
I hope it helps! Have a great day!
Anygays-
