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3 years ago

Guys help me with this question.

Physics

1 answer:

sleet_krkn [62]3 years ago

4 0

Answer:

Explanation:

Brownian motion is a random (irregular) motion of particles e.g smoke particle. The set up in the diagram can be used to observe the motion of smoke.

1. The apparatus used are:

A is a source of light

B is a converging lens

C is a glass smoke cell

D is a microscope

2. The uses of the apparatus are:

A - produces the light required to so as to see clearly the movement of the particles.

B - converges the rays of light from the source to the smoke cell.

C - is made of glass and used for encamping the smoke particles so as not to mix with air.

D - is used for the clear view or observation or study of the motion of the smoke particles in the cell.

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One airplane is approaching an airport from the north at 181 kn/hr. A second airplane approaches from the east at 278 km/hr. Fin

umka2103 [35]

Answer:

The value is $\frac{dR}{dt} = -286.2 \ km/hr$

Explanation:

From the question we are told that

The speed of the airplane from the north is $\frac{dN}{dt} = -181 \ km /hr$

The negative sign is because the direction is towards the south

The speed of the airplane from the east is $\frac{dE}{dt} = -278 \ km/hr$

The negative sign is because the direction is towards the west

The distance of the southbound plane from the airport is $N = 30 \ km$

The distance of the westbound plane is $E = 15 \ km$

Generally the distance between the plane is mathematically represented using Pythagoras theorem as

$R^2 = N^2 + E^2$

Next differentiate implicitly this equation to obtain the rate at which the distance between the planes changes

$2R\frac{dR}{dt} = 2N \frac{dN}{dt} + 2E\frac{dE}{dt}$

Here

$R = \sqrt{N^2 + E^2}$

=> $R = \sqrt{30^2 + 15^2}$

=> $R =33.54 \ m$

$2(33.54) * \frac{dR}{dt} = 2( 30)*(-181) + 2*15*(-278)$

=> $67.08 * \frac{dR}{dt} = -19200$

=> $\frac{dR}{dt} = -286.2 \ km/hr$

4 0

3 years ago

At the top of a giant swing on the gymnastics high bar, candy's velocity is 1 m/s, and she is 3.5 m high. if candy's mass is 50

Allushta [10]

The total mechanical energy is the sum of the kinetic energy and the gravitational potential energy:
$E=K+U= \frac{1}{2}mv^2 +mgh$
where m=3.5 kg is Candy's mass, v=1 m/s is her velocity and h=3.5 m is her height. If we replace these numbers, we find the mechanical energy of the system:
$E= \frac{1}{2} (50 kg)(1m/s)^2 + (50 kg)(9.81 m/s^2)(3.5 m)=1742 J =1.74 kJ$

6 0

2 years ago

Click on the reset button, and stack one 50kg. crate on top of the other, so that the total mass is 100kg. The Friction should b

Helen [10]

Answer:

490.5 N

Explanation:

Coefficient of friction is 0.5 since friction force is set to halfway between none and lots. Minimum force is given by multiplying the weight and coefficient of friction

F= kN where k is coefficient of friction while N is weight. Also, N=mg where m is mass and g is acceleration due to gravity.

F=kmg=0.5*100*9.81=490.5 N

6 0

3 years ago

Which of these stopped operating in 2011

Vladimir [108]

D. space shuttle program

8 0

3 years ago

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What is the speed of a car that travels 50m in 25min? *

ArbitrLikvidat [17]

Answer:

the speed is 2

Explanation:

speed= distance/ time

speed= 50/25

= 2

hope this helps!

4 0

2 years ago

Read 2 more answers

Guys help me with this question.​

Guys help me with this question.