So3 +H2so4----H2s2o7????? How??

(1 pt) You have 250.0 mL of 0.136 M HCl. Using a volumetric pipet, you take 25.00 mL of that solution, place it in a 100.00 ml v

alexdok [17]

Answer:

0.034M HCl is the concentration of the diluted solution

Explanation:

You take, initially, 25.00mL of the 0.136M HCl. Then, you dilute the solution to 100.00mL. The solution is diluted:

100.00mL / 25.00mL = 4. The solution was diluted 4 times.

That means the concentration of the diluted solution is:

0.136M / 4 =

<h3>0.034M HCl is the concentration of the diluted solution</h3>

7 0

3 years ago

An object sliding along a horizontal table is an example of projectile motion.

Mumz [18]

True because if anything is moving it is in motion. And because horizontal is similar to projectile!

5 0

3 years ago

Read 2 more answers

Why was Newland’s periodic table rejected?

Rina8888 [55]

He put iron with sulfur and oxygen and it had a few more errors and iron is a metal the other two are nonmetals

5 0

3 years ago

In Part III, the phenolphthalein indicator is used to monitor the equilibrium shifts of the ammonia/ammonium ion system. The phe

AnnZ [28]

The pink color in the solution fades. Some of the colored indicator ion converts to the colorless indicator molecule.

<h3>Explanation</h3>

What's the initial color of the solution?

$\text{NH}_4\text{Cl}$ is a salt soluble in water. $\text{NH}_4\text{Cl}$ dissociates into ions completely when dissolved.

$\text{NH}_4\text{Cl} \; (aq)\to {\text{NH}_4}^{+} \; (aq) +{\text{Cl}}^{-} \; (aq)$ .

The first test tube used to contain $\text{NH}_4\text{OH}$ . $\text{NH}_4\text{OH}$ is a weak base that dissociates partially in water.

$\text{NH}_4\text{OH} \; (aq) \rightleftharpoons {\text{NH}_4}^{+} \;(aq)+ {\text{OH}}^{-} \; (aq)$ .

There's also an equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$ .

$\text{OH}^{-}$ ions from $\text{NH}_4\text{OH}$ will shift the equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ to the right and reduce the amount of ${\text{H}_3\text{O}}^{+}$ in the solution.

The indicator equilibrium will shift to the right to produce more ${\text{H}_3\text{O}}^{+}$ ions along with the colored indicator ions. The solution will show a pink color.

What's the color of the solution after adding NH₄Cl?

Adding $\text{NH}_4\text{Cl}$ will add to the concentration of ${\text{NH}_4}^{+}$ ions in the solution. Some of the ${\text{NH}_4}^{+}$ ions will combine with $\text{OH}^{-}$ ions to produce $\text{NH}_4\text{OH}$ .

The equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions will shift to the left to produce more of both ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$

The indicator equilibrium will shift to the left as the concentration of ${\text{H}_3\text{O}}^{+}$ increases. There will be less colored ions and more colorless molecules in the test tube. The pink color will fade.

7 0

3 years ago

Which of the following represents a 1.00 M (M = mol/dm3) aqueous solution of glucose (C6H12O6)?

irga5000 [103]

The answer would be c

4 0

3 years ago