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2 years ago

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NEED HELP PLEASE ASAP

1 answer:

Vladimir [108]2 years ago

8 0

12 kWh.

The input energy = 36kWh divide by 0.75 = 48kWh

The lost energy = 0.25 x 48kWh = 12kWh

because 25% of input energy is lost to the surrounding.

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A particular engine has a power output of 5 kW and an efficiency of 30%. If the engine expels 6464 J of thermal energy in each c

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Answer:

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Explanation:

Given;

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let the heat absorbed = $Q_h$

The efficiency of the engine is given as;

$e = \frac{W}{Q_h} = \frac{Q_h-Q_c}{Q_h} = \frac{Q_h}{Q_h} - \frac{Q_c}{Q_h} = 1-\frac{Q_c}{Q_h}\\\\e = 1-\frac{Q_c}{Q_h}\\\\0.3 = 1-\frac{Q_c}{Q_h}\\\\\frac{Q_c}{Q_h} = 1-0.3\\\\\frac{Q_c}{Q_h} = 0.7\\\\Q_h = \frac{Q_c}{0.7} \\\\Q_h = \frac{6464}{0.7} = 9,234.286 \ J.$

Therefore, the heat absorbed in each cycle is 9,234.286 J.

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A 200-N woman is standing on a concrete floor. How much force does the floor exert on her?

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The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m

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$K.E+\dfrac{kq_{1}q_{2}}{d}=\dfrac{kq_{1}q_{2}}{x}+K.E$

Put the value into the formula

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