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krek1111 [17]
3 years ago
12

g a stone with mass m=1.60 kg IS thrown vertically upward into the air with an initial kinetic energy of 470 J. the drag force a

cting on the stone throughout its flight is constant, independent of the velocity of the stone, and has a magnitude of 0.900 N. what is the maximum height reached by the stone?
Physics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

Height reached will be 28.35 m

Explanation:

Here we can use the work energy theorem to find the maximum height

As we know by work energy theorem

Work done by gravity + work done by friction = change in kinetic energy

-mgh - F_f h = 0 - \frac{1}{2}mv_i^2

now we will have

-1.60(9.8)(h) - 0.900(h) = - 470

-16.58 h = -470

h = 28.35 m

so here the height raised by the stone will be 28.35 m from the ground after projection in upward direction

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Answer:

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Explanation:

The quantity of electricity i.e charge is related to current and time according to the equation equation:

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I => is the current.

t => is the time.

Thus, we can rearrange the above expression to make 'I' the subject. This is illustrated below:

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2633.7 s

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