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krek1111 [17]
3 years ago
12

g a stone with mass m=1.60 kg IS thrown vertically upward into the air with an initial kinetic energy of 470 J. the drag force a

cting on the stone throughout its flight is constant, independent of the velocity of the stone, and has a magnitude of 0.900 N. what is the maximum height reached by the stone?
Physics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

Height reached will be 28.35 m

Explanation:

Here we can use the work energy theorem to find the maximum height

As we know by work energy theorem

Work done by gravity + work done by friction = change in kinetic energy

-mgh - F_f h = 0 - \frac{1}{2}mv_i^2

now we will have

-1.60(9.8)(h) - 0.900(h) = - 470

-16.58 h = -470

h = 28.35 m

so here the height raised by the stone will be 28.35 m from the ground after projection in upward direction

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Explanation:

Amperage is the unit of electric current. It describes the strength of the electric current in a circuit.

The voltage is the driving force of the current in a circuit

Power is a function of voltage and current in the circuit.

   Current is designate as I

    Voltage as V

    Power as P

  I = \frac{V}{R}

Where R is the resistance to flow of electricity

        P = I x V = \frac{V^{2} }{R}

The unit of power is watts and voltage is volts

learn more:

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8 0
3 years ago
What combination of things happen on earth that helps make wind, and the weather on earth? (Please list at least two factors, an
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Answer:

There are six main components, or parts, of weather. They are <u>temperature, atmospheric pressure, wind, humidity, precipitation, and cloudiness</u>. Together, these components describe the weather at any given time. These changing components, along with the knowledge of atmospheric processes, help meteorologists—scientists who study weather—forecast what the weather will be in the near future.

8 0
2 years ago
A spinning wheel is slowed down by a brake, giving it a constant angular acceleration of ?5.20 rad/s2. during a 3.80-s time inte
ddd [48]

<span>We can answer this using the rotational version of the kinematic equations:</span><span>
θ = θ₀ + ω₀<span>t + ½αt²     -----> 1</span></span>

ω² = ω₀² + 2αθ            -----> 2

Where:

θ = final angular displacement = 70.4 rad

θ₀ = initial angular displacement = 0

ω₀ = initial angular speed

ω = final angular speed

t = time = 3.80 s

α = angular acceleration = -5.20 rad/s^2

Substituting the values into equation 1:<span>
70.4 = 0 + ω₀(3.80) + ½(-5.20)(3.80)² </span><span>

ω₀ = (70.4 + 37.544) / 3.80 </span><span>

ω₀ = 28.406 rad/s </span><span>


Using equation 2:
ω² = (28.406)² + 2(-5.2)70.4 


ω = 8.65 rad/s 


</span>

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3 years ago
A block pushed with a force of 27 N accelerates at 5 m/s2. What is the mass of the block?
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Explanation:

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=5.2kg

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sam drove 44 meters to the right . she drove 13 meter to the left . what was her displacement ? what is displacement ?
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The displacement was 31
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