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Archy [21]
2 years ago
5

Price controls on rents are frequently implemented by governments in an effort to protect renters from high housing prices. Diff

erentiate the type of price control used from other potential price controls, and then formulate reasons as to why governments should be careful when implementing these types of controls.
PLZ I NEED HELP!!
Physics
1 answer:
Pavlova-9 [17]2 years ago
7 0

The most common price control is setting a fixed rent price to protect the tenants. There are other alternatives to this price control. Also, price control should be carefully implemented.

Rent regulation is a term that refers to a set of laws that focus on ensuring that individuals have access to rented housing.

The rental regulation system has a principe that is:

  • Price controls: Set a rent price and set the increase in a percentage of it (the rent is $ 100 and the annual increase is 5%)

There are alternatives price control such as:

  • Price according to the type of property: Set a rental price according to the type of property and its benefits (for example pool, garage, garden, etc)
  • Price according to the number of tenants: Set a rental price according to the number of people who will inhabit the property

Generally, tenants are allowed to raise the value of the rent each year by a minimal proportion. This is necessary to avoid that the landlord does not increase the rental value in large amounts because the tenant will not have access to the rented house.

However, governments should be careful with this regulations because they can negative afect the landlord by limiting his rights over the property.

Learn more in:

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Parker (73.2 kg) is being dragged down the hall with an applied force of 123 N. If the frictional force is 27.4 N, what is the c
levacccp [35]

Answer:

The coefficient of friction in the hall is 0.038

Explanation:

Given;

mass of the Parker, m = 73.2 kg

applied force on the parker, F = 123 N

frictional force, Fs = 27.4 N

the coefficient of friction in the hall = ?

frictional force is given by;

Fs = μN

Where;

μ is the coefficient of friction

N is normal reaction = mg

Fs = μmg

μ = Fs / mg

μ = (27.4) / (73.2 x 9.8)

μ = 0.038

Therefore, the coefficient of friction in the hall is 0.038

6 0
3 years ago
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.275 T. If the kinetic energy of the electr
xxMikexx [17]

Answer:

Radius, r=2.14\times 10^{-5}\ m

Explanation:

It is given that,

Magnetic field, B = 0.275 T

Kinetic energy of the electron, E=4.9\times 10^{-19}\ J

Kinetic energy is given by :

E=\dfrac{1}{2}mv^2

v=\sqrt{\dfrac{2E}{m}}

v=\sqrt{\dfrac{2\times 4.9\times 10^{-19}}{9.1\times 10^{-31}}}            

v = 1037749.04 m/s

The centripetal force is balanced by the magnetic force as :

qvB\ sin90=\dfrac{mv^2}{r}

r=\dfrac{mv}{qB}

r=\dfrac{9.1\times 10^{-31}\times 1037749.04}{1.6\times 10^{-19}\times 0.275 }

r=2.14\times 10^{-5}\ m

So, the radius of the circular path is 2.14\times 10^{-5}\ m. Hence, this is the required solution.

3 0
3 years ago
Read 2 more answers
How many water (in kg) can raise its temperature from 23°C to 100°C by adding 21500 Joules of energy?
igomit [66]

Answer: Approximately 8.0g of water

Explanation:

4 0
3 years ago
The bird that migrates the farthest is the Arctic tern. Each year, the Arctic tern travels
Tanzania [10]

Answer: 131.14km per day

Explanation: since the second half of the terns migration takes 122 days we can assume that the full migration would take 244 days. using this we can divide the total distance by the total amount of days it takes (because speed = distance/time) which is 32,000/244, which would be 131.14

8 0
2 years ago
The distance between adjacent nodes in a standing wave pattern in a length of string is 25.0 cm:A. What is the wavelength of wav
mina [271]

A) 50 cm

B) 10000 cm/s

Explanation

Step 1

A)

If you know the distance between nodes and antinodes then use this equation:

\begin{gathered} \frac{\lambda}{2}=D \\ \text{where}\lambda\text{ is the wavelength} \\ D\text{ is the distance betw}een\text{ nodes} \end{gathered}

then, let

D=\text{ 25 cm }

now, replace to find the wavelength

\begin{gathered} \frac{\lambda}{2}=25 \\ \text{Multiply both sides by 2} \\ \frac{\lambda}{2}\cdot2=25\cdot2 \\ \lambda=50\text{ Cm} \end{gathered}

so, the wavelength is

A) 50 cm

Step 2

The speed of a wave can be found using the equation

v=\lambda f

or velocity = wavelength x frequency,

then,let

\begin{gathered} \lambda=50\text{ cm} \\ f=200\text{ Hz} \end{gathered}

replace and evaluate

\begin{gathered} v=\lambda f \\ v=50\text{ cm }\cdot200\text{ HZ} \\ v=10000\text{ }\frac{\text{cm}}{s} \end{gathered}

so

B) 10000 cm/s

I hope this helps you

6 0
1 year ago
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