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sergeinik [125]
2 years ago
5

Why can rock avalanches move downslope at speeds exceeding 200 km/hr (125 mi/hr)?

Physics
1 answer:
Sati [7]2 years ago
5 0

Rock avalanches move downslope at speeds exceeding 200 km/hr (125 mi/hr) because when the soil expands and compresses, it lifts certain particles and drops them downslope a short distance.

Landslides are the common name for soil or rock avalanches. The most frequent type of avalanche, snowslides, can travel downhill more quickly than a skier. When an unstable snow mass detaches from a slope, a snow avalanche starts.

Rock avalanches are caused by the rapid breakup of initially intact, highly fast-moving rock masses during transportation. In mountainous areas, rock avalanches, which are unexpected rock slope failures marked by high velocities, lengthy runouts, and massive volumes, are among the most deadly and costly geological hazards.

To learn more about Rock avalanches please visit -
brainly.com/question/12661230
#SPJ4

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Photosynthesis occurs in a plant cell's
Fynjy0 [20]

Answer:

Photosynthesis occurs in the organelle, chloroplast .

Cellular respiration occurs in a plants or animals mitochondria.

Explanation:

Hope this helps! :)

5 0
3 years ago
There is much debate about whether or not global warming exists and whether people and their actions are to blame. High levels o
sergiy2304 [10]
<span>C) Humans and their activities do not affect the natural cycles of the Earth

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4 0
4 years ago
Read 2 more answers
At an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s. What is the angle of the shock cone
Ber [7]

Answer:

55 degrees

Explanation:

Given that an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s.

From the question above, we can get the below parameters

Object speed (V) = 1500 km/h

Sound speed ( v) = 342 m/s

Convert km/h to m/s

(1500 × 1000)/3600

Jet speed V = 416.67 m/s

Let's first calculate the mash number M.

M = V/v

M = 416.67 / 342

M = 1.2183

Formula for the angle of the shock cone is reciprocal of mash number. That is,

Sin Ø = 1 / M

Sin Ø = 1 / 1.2183

Sin Ø = 0.8208

Ø = sin^-1(0.8208)

Ø = 55 degree

Therefore, the angle of the shock cone is approximately 55 degrees

5 0
3 years ago
A 3.04 kg particle is located on the x-axis at xm = −8 m, and a 5.61 kg particle is on the x-axis at xM = 3.56 m. Find the coord
Murljashka [212]

Answer:

center of mass = −0.50 m

Explanation:

given data

mass m1 = 3.04 kg

distance xm = -8 m

mass m2 = 5.61 kg

distance xM = 3.56 m

solution

we get here center of mass for n mass of system that is express as

center of mass = \frac{m_1x_1+m_2x_2......m_nx_n}{m_1+m_2...m_n}     ......................1

but we have only 2 particle system so we will get

center of mass = \frac{m1 \times xm+m2 \times xM}{m1+m2}      .................2

put here value and we will get

center of mass = \frac{3.04 \times (-8 )+5.61 \times 3.56}{3.04 + 5.61}

solve it we will get

center of mass = −0.50 m

8 0
4 years ago
A COPPER WIRE OF LENGTH 4M AND AREA OF CROSS-SECTION 1.2CM^2 IS STRECHED WITH A FORCE 4.8×10^3 N . IF YOUNGS MODULAS FOR COPPER
VARVARA [1.3K]

Stress = force / area

= 4.8 x 10³ / 1.2 x 10^-4

= 4 x 10⁷ N /m²

YOUNGS MODULAS = stress / strain

= 4 x 10⁷ / 1.2 x 10^11

= 3.3 x 10^-4

INCREMENT OF LENGTH = longitudinal length x intitial length

= ( 3.3 x 10^-4 ) x 4

= 13.2 x 10^-4 m

= 13.2 mm

mark ‼️ it brainliest if it helps you ❤️

6 0
3 years ago
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