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2 years ago

After watching the video below and based on your personal experiences, is there a difference

1 answer:

3 0

Based on my personal experiences, I believe that there is a difference between areas in precision of control because there are different part of the brain that controls the functions of the body.

<h3>What is the difference between left-handed and right-handed people?</h3>

From the standpoint of brain lateralization, differences do exist such as based on experience such as handedness or specific skills such as playing a guitar.

Note that Left-handers are said to have reduced or little lateralized brains, which tells us that the two halves of the brain are little different than as seen in the right-handers.

Therefore, I can say that based on my personal experiences, I believe that there is a difference between areas in precision of control because there are different part of the brain that controls the functions of the body.

Learn more about brain from

brainly.com/question/1247675

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You might be interested in

Tycho used his high accuracy observations to conclude that the Earth revolves around the sun. Tycho used his high accuracy obser

Amiraneli [1.4K]

Answer:

False

Explanation:

Tycho Brahe, who was a Dutch Astronomer of 16th Century AD, did not conclude the Earth revolves around the Sun which was the Heliocentric Model as stated by Copernicus. Tycho proposed a Geo-Heliocentric model in which the Sun and the Moon used to revolve around the Earth but other planets used to revolve around the Sun.

He also believed that the Heliocentric model was in violation with the Holy Scriptures.

6 0

4 years ago

Fitness tests check to see how physically fit you are. How can a fitness assessment help you to improve your fitness? What area

mixer [17]

Fitness assessment can help us to improve our fitness simply by setting goals to improve their healthy fitness

However, fitness testing is an effective strategy to monitor and assess our fitness levels in general as it helps us to understand how healthy they are by learning about the five components of fitness .

<h3>What is physical fitness?</h3>

This simply refers to a state of an individual being physically healthy.

In order words, it is a condition of being physically fit and healthy.

So therefore, fitness assessment can help you to improve our fitness simply by setting goals to improve their health-related fitness

Learn more about fitness:

brainly.com/question/24364238

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4 0

2 years ago

In a material for which o=5.0 S/m and e, =1 the electric field intensity is E- 250 sin 10" (V/m). Find the conduction and displa

Elodia [21]

Answer:

Explanation:

Given that:

The conductivity of the material $\sigma$ = 5.0 s/m

$The \ relative \ permittivity \ of \ the \ material$ ${\varepsilon_r} = 1$ ; &

The electric field intensity of the material E = 250 sin(10¹⁰ t) V/m

(a) The conduction current density $( J_c) = \sigma E$

$= 5.0 \times 250 \ sin ( 10^{10} \ t )$

$\mathbf{ = 1250 \ sin (10 ^{10} t ) \ A/m^2 }$

(b) Displacement current density $(J_d) = \varepsilon _d * \dfrac{\delta E}{\delta t}$

Recall that:

$\varepsilon _o = 8.854 \times 10^{-12}$

∴

$(J_d) = 8.854 \times 10^{-12} \times \dfrac{d}{dt} \times (250 \ sin \ (10^{10} \ t))$

$(J_d) = 8.854 \times 10^{-12} \times 250 \times 10^{10} \times \ cos \ (10^{10} \ t)$

$(J_d) = 22.135 \ cos \ 10^{10} \ t \ A/m^2$

$f = \dfrac{\sigma}{2 \pi \varepsilon_o \varepsilon_r}$

By substitution

$f = 18 \times 10^9 \times \dfrac{\sigma }{\varepsilon_r}$

$f = 18\times 10^9 \times \dfrac{5}{1 }$

f = 90 GHz

5 0

3 years ago

A book prone to air resistance is released from rest 300 m

yaroslaw [1]

Answer:

Approximately $73\%$ .

(Assuming that $g = \rm 9.81\; m \cdot s^{-2}$ .)

Explanation:

The mechanical energy of an object is the sum of its potential energy and its kinetic energy. It will be shown that the exact mass of this object doesn't matter. For ease of calculation, let $m(\text{book})$ represent the mass of the book.

The initial potential energy of the book is

$\begin{aligned}U(300\; \text{m}) &= m(\text{book}) \cdot g \cdot \Delta h + U(0\; \text{m}) \cr &=(9.81 \times 300) \cdot m(\text{book})\cr &= \left(2.943\times 10^3\right) \cdot m(\text{book})\end{aligned}$ .

The book was initially at rest when it was released. Hence, its initial kinetic energy would be zero. Hence, the initial mechanical energy of the book-Earth system would be $(2.943\times 10^3) \cdot m(\text{book})$ .

When the book was about to hit the ground, its speed is $\rm 40\; m \cdot s^{-1}$ . Its kinetic energy would be:

$\begin{aligned} \text{KE} &= \frac{1}{2} \, m(\text{book}) \cdot v^{2} \cr &= \left(\frac{1}{2} \times 40^2\right)\cdot m(\text{book}) \cr &= \left(8.00\times 10^2\right)\cdot m(\text{book})\end{aligned}$ .

The question implies that the potential energy of the book near the ground is zero. Hence, the mechanical energy of the system would be $\left(8.00\times 10^2\right)\cdot m(\text{book})$ when the book was about to hit the ground.

The amount of mechanical energy lost in this process would be equal to:

$\begin{aligned}&\left(2.943\times 10^3\right) \cdot m(\text{book}) - \left(8.00\times 10^2\right)\cdot m(\text{book}) \cr &=\left(2.143\times 10^3\right)\cdot m(\text{book})\end{aligned}$ .

Divide that with the initial mechanical energy of the system to find the percentage change. Note how the mass of the book, $m(\text{book})$ , was eliminated in this process.

$\begin{aligned}&\frac{\left(2.143\times 10^3\right)\cdot m(\text{book})}{\left(2.943\times 10^3\right) \cdot m(\text{book})}\times 100\% \cr &= \frac{2.143\times 10^3}{2.943\times 10^3}\times 100\% \cr & \approx 73\%\end{aligned}$ .

5 0

4 years ago

Which time interval has the greatest speed?

shutvik [7]

Answer:

es la 2

Explanation:

epero que te curva

4 0

3 years ago