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jasenka [17]
3 years ago
9

1-¿Que tipo de energía usa en su hogar para el alumbrado , la calefacción y artículos de entretenían, entre otros ? 2-¿ de que m

anera en su hogar o escuela tienen acceso a la energía eléctrica? 3- aparte de los componentes ¿ hay alguna diferencia en el funcionamiento de circuito eléctrico de una linterna y el de una casa ? 4-¿que ocurriría si el voltaje que proporciona la fuente de energía es menor que la requerida por la ampolleta ? ¿Y su es mayor? 5-es indispensable el interruptor para el funcionamiento del circuito eléctrico
Physics
1 answer:
Harman [31]3 years ago
5 0

Answer:

Explanation:

1.-Energía eléctrica ( electricidad ) proveniente de una fuente AC ( es decir de corriente alterna)

2.-Hay un proveedor de servicios que lleva la energía a las comunidades en general y en particular la lleva hasta mi casa y escuela. Se define como acometida eléctrica, la infraestructura que lleva la energía desde la red de distribución al tablero principal en el abonado. La acometida puede ser aérea o subterránea, y normalmente consta de tres conductores ( de los cuales dos son calibre AWG # 8 ( dos fases ) y uno AWG # 10 ( neutro ). Esta configuración permite tener: 120 y 240 (V) en servicio en la casa y suficiente capacidad para la carga eléctrica de una casa normal

3.-Si, el tipo de corriente. En el caso de una linterna se usan "pilas" o baterías de corriente directa ( que no varia en el tiempo), en la casa la corriente es alterna de 60 ciclos por segundo de frecuencia.

4.-Si el voltaje es menor en una medida importante la ampolleta no alumbra por cuanto si por ejemplo el voltaje nominal ( o de funcionamiento es 120 V y el voltaje suministrado es 50 V ese voltaje será insuficiente para hacer funcionar el circuito). Si el voltaje es mayor dígamos 240 V la ampolleta se quema.

5.-El interruptor nos asegura la maniobra a nuestra voluntad del circuito del cual forma parte. Es decir si tengo un circuito de alumbrado ( 1 bombillo y un interruptor ) ese interruptor me permitirá apagar y encender la luz cuando yo quiera.

Los breaker son "interruptores" son dispositivos de protección para caso de sobrecargas y/o cortocircuitos

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Two objects attract each other gravitationally. If the distance between their centers decreases by a factor of 2, how does the g
kramer

Answer:

The gravitational force between them increases by a factor of 4

Explanation:

Gravitational force is a force of attraction between two objects with masses M and m which are separated by a distance R. It is given mathematically as:

Fg = GMm/R²

Where G = Gravitational constant.

If the distance between their centers, R, decreases by a factor of 2, then it means the new distance between their centers is:

r = R/2

Hence,the gravitational force becomes:

Fg = GMm/r²

Fg = GMm/(R/2)²

Fg = GMm/(R²/4)

Fg = 4GMm/R²

Hence,the gravitational force increases by a factor of 4.

6 0
3 years ago
The 1.53-kg uniform slender bar rotates freely about a horizontal axis through O. The system is released from rest when it is in
OlgaM077 [116]

Answer:

The spring constant = 104.82 N/m

The angular velocity of the bar when θ = 32° is 1.70 rad/s

Explanation:

From the diagram attached below; we use the conservation of energy to determine the spring constant by using to formula:

T_1+V_1=T_2+V_2

0+0 = \frac{1}{2} k \delta^2 - \frac{mg (a+b) sin \ \theta }{2}  \\ \\ k \delta^2 = mg (a+b) sin \ \theta \\ \\ k = \frac{mg(a+b) sin \ \theta }{\delta^2}

Also;

\delta = \sqrt{h^2 +a^2 +2ah sin \ \theta} - \sqrt{h^2 +a^2}

Thus;

k = \frac{mg(a+b) sin \ \theta }{( \sqrt{h^2 +a^2 +2ah sin \ \theta} - \sqrt{h^2 +a^2})^2}

where;

\delta = deflection in the spring

k = spring constant

b = remaining length in the rod

m = mass of the slender bar

g = acceleration due to gravity

k = \frac{(1.53*9.8)(0.6+0.2) sin \ 64 }{( \sqrt{0.6^2 +0.6^2 +2*0.6*0.6 sin \ 64} - \sqrt{0.6^2 +0.6^2})^2}

k = 104.82\ \  N/m

Thus; the spring constant = 104.82 N/m

b

The angular velocity can be calculated by also using the conservation of energy;

T_1+V_1 = T_3 +V_3  \\ \\ 0+0 = \frac{1}{2}I_o \omega_3^2+\frac{1}{2}k \delta^2 - \frac{mg(a+b)sin \theta }{2} \\ \\ \frac{1}{2} \frac{m(a+b)^2}{3}  \omega_3^2 +  \frac{1}{2} k \delta^2 - \frac{mg(a+b)sin \ \theta }{2} =0

\frac{m(a+b)^2}{3} \omega_3^2  + k(\sqrt{h^2+a^2+2ah sin \theta } - \sqrt{h^2+a^2})^2 - mg(a+b)sin \theta = 0

\frac{1.53(0.6+0.6)^2}{3} \omega_3^2  + 104.82(\sqrt{0.6^2+0.6^2+2(0.6*0.6) sin 32 } - \sqrt{0.6^2+0.6^2})^2 - (1.53*9.81)(0.6+0.2)sin \ 32 = 0

0.7344 \omega_3^2 = 2.128

\omega _3 = \sqrt{\frac{2.128}{0.7344} }

\omega _3 =1.70 \ rad/s

Thus, the angular velocity of the bar when θ = 32° is 1.70 rad/s

7 0
2 years ago
31) The basic concept of how a simple motor works is explained by which statement?
Firdavs [7]

Answer:

When a wire that carries electrical current is placed in a magnetic field the wire experiences a force.

Explanation:

The electric motor is a device which convert electrical energy into mechanical energy  ie when current carrying conductor is placed in magnetic field it experience a force. Flemings left hand rule explains the direction of the current.

The electric motor works by attraction and repulsion of magnetic field.

So the option d explains basic concept of simple motor ie when when current carrying wire is placed in the magnetic field it experience magnetic repulsive force.

5 0
3 years ago
if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.​
Likurg_2 [28]

Answer:

4 seconds

Explanation:

Given:

v₀ = 20 m/s

v = 0 m/s

a = -5 m/s²

Find: t

v = at + v₀

0 m/s = (-5 m/s²) t + 20 m/s

t = 4 s

6 0
3 years ago
Natural history research involves ____ unobsevable and unrepeatable past events.
Tanzania [10]
B verifying is the answer
4 0
3 years ago
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