Answer:
6.5 m/s
Explanation:
We are given that
Distance, s=100 m
Initial speed, u=1.4 m/s
Acceleration, ![a=0.20 m/s^2](https://tex.z-dn.net/?f=a%3D0.20%20m%2Fs%5E2)
We have to find the final velocity at the end of the 100.0 m.
We know that
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
Using the formula
![v^2-(1.4)^2=2\times 0.20\times 100](https://tex.z-dn.net/?f=v%5E2-%281.4%29%5E2%3D2%5Ctimes%200.20%5Ctimes%20100)
![v^2-1.96=40](https://tex.z-dn.net/?f=v%5E2-1.96%3D40)
![v^2=40+1.96](https://tex.z-dn.net/?f=v%5E2%3D40%2B1.96)
![v^2=41.96](https://tex.z-dn.net/?f=v%5E2%3D41.96)
![v=\sqrt{41.96}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B41.96%7D)
![v=6.5 m/s](https://tex.z-dn.net/?f=v%3D6.5%20m%2Fs)
Hence, her final velocity at the end of the 100.0 m=6.5 m/s
PE = (mass) (gravity) (height)
PE = (0.005 kg) (9.8 m/s²) (5 m)
<em>PE = 0.245 Joule</em>
...............................................................
The momentum change =mass*velocity change. But sincevelocity change is not known another strategy must be used to find the momentum change. The strategy involves first finding the impulse (F*t = 1.0 N*s). Since impulse = momentum change, the answer is 1.0 N*s.
Answer:
So height will be 47.387 m
Explanation:
We have given gauge pressure ![P=4.63\times 10^5N/m^2](https://tex.z-dn.net/?f=P%3D4.63%5Ctimes%2010%5E5N%2Fm%5E2)
Density of water ![\rho =997kg/m^3](https://tex.z-dn.net/?f=%5Crho%20%3D997kg%2Fm%5E3)
Acceleration due to gravity ![g=9.8m/sec^2](https://tex.z-dn.net/?f=g%3D9.8m%2Fsec%5E2)
We know that pressure is given as ![P=\rho gh](https://tex.z-dn.net/?f=P%3D%5Crho%20gh)
![4.63\times 10^5=997\times 9.8\times h](https://tex.z-dn.net/?f=4.63%5Ctimes%2010%5E5%3D997%5Ctimes%209.8%5Ctimes%20h)
![h=47.387m](https://tex.z-dn.net/?f=h%3D47.387m)
So height will be 47.387 m