Question

a lamp post has half of its length in mud,1 by 3 of its length in water and 3 whole 1by3m above water. find the whole length of the post​

Answer 1

Answer:

20 m

Step-by-step explanation:

Given:

• Length in mud = ¹/₂ its length
• Length in water = ¹/₃ its length
• Length above water = 3 ¹/₃ m

Let x be the length of the lamp post.

Convert 3 ¹/₃ to an improper fraction:

$\sf \implies 3 \frac{1}{3}=\dfrac{3 \times 3+1}{3}=\dfrac{10}{3}$

The total length of the lamp post (x) is the sum of the three given lengths:

$\implies \sf mud+water+above\: water=x$

$\sf \implies \dfrac{x}{2}+\dfrac{x}{3}+\dfrac{10}{3}=x$

Multiply both sides by 6:

$\sf \implies \dfrac{6x}{2}+\dfrac{6x}{3}+\dfrac{6 \cdot 10}{3}=6x$

$\sf \implies 3x+2x+20=6x$

$\sf \implies 5x+20=6x$

Isolate x:

$\sf \implies 20=6x-5x$

$\implies \sf x=20$

Therefore, the whole length of the post is 20 m.

Answer 2

Answer: 20m

Step-by-step explanation: Correct option is A)

Let the total  length of the post be x m

Then length of post in mud= x/2

​Length of post in water = x/3

Given

x/2-x/3=10/3

x/6=10/3

x=20

​