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SVEN [57.7K]
3 years ago
13

How the metals react with oxygen? Give the general formula and explain the reaction of sodium with oxygen with chemical equation

.​
Chemistry
1 answer:
slamgirl [31]3 years ago
4 0

Answer:

Sodium is a very reactive metal, it tends to react with oxygen to form sodium oxide but this is an unstable compound and soon reacts with hydrogen to form sodium hydroxide. Sodium is the metal reacts vigorously with oxygen and water.

4 Na + O2 → 2 Na2O.

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3 years ago
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How many moles of gaseous boron trifluoride, BF3, are contained in a 4.3410 L bulb at 788.0 K if the pressure is 1.220 atm What
gregori [183]

Answer:

n= 0.08186

{He}2s^2 2p^6

Explanation:

PV=nRT

n=PV/RT

n= (1.220 atm)(4.3410 L) / (0.0821 atm*L/mol*K)(788.0 K)

n=0.08186

As for the electron configuration:

Ne:

{He} 2s^2 2p^6

or long hang:

1s^2 2s^2 2p^6

5 0
3 years ago
Based on the information provided here, crude oil is:
Anna007 [38]

THE EXPLINATION ANSWER: I think crude oil is a mixture because it is made up of compounds that can be separated using distillation, a physical process.

8 0
3 years ago
Las formulas de quimica
Veseljchak [2.6K]

Answer:

The chemistry formulas are formed by the chemical reactions of chemical substances.

Explanation:

The chemical substances are introduced together to find the chemical reactions and then equations are formed. The equations them used to form the formulas for the chemical reactions that are performed. The quantity of the acid and base need to be carefully introduced when performing a titration process.

3 0
3 years ago
Ans with solution...
Licemer1 [7]

Answer:

The answer to your question is:

Vol of NO2 = 11.19 L

Vol of O2 = 2.8 L

Explanation:

Data

N2O5 = 56 g

STP     T = 0°C = 273°K

           P = 1 atm

MW N2O5 = 216 g

Gases law = PV = nRT

Process

                   216 g of N2O5 ---------------- 1 mol

                     54 g               -----------------  x

                    x = (54 x 1) / 216

                    x = 0.25 mol of N2O5

                   2 mol of N2O5 -----------------  4 mol of NO2

                   0.25 mol          ------------------    x

                   x = (0.25 x 4) / 2 = 0.5 mol of NO2

                   V = nRT/P

                   V = (0.5)(0.082)(273) / 1 = 11.19 L

                   2 mol of N2O5 ----------------- 1 O2

                   0.25 N2O5 ----------------------  x

                   x = (0.25 x 1) / 2 = 0.125 mol

                   Vol = (0.125)((0.082)(273) / 1 = 2.8 L

3 0
4 years ago
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