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Aleks04 [339]
2 years ago
15

The sodium atom loses an electron to form a sodium ion (Na+). Which statement is correct with respect to its atomic radius?

Chemistry
2 answers:
My name is Ann [436]2 years ago
6 0

The atomic number of sodium is 11. Sodium is a metal and it has the electronic configuration: 2, 8,1. This configuration implies that, the electrons in an atom of sodium are distributed into three different shells and the outermost shell has one electron in it. If sodium decide to give away the electron on its outermost shell, it will have 10 electrons left and those electrons will be distributed in only the first two shells and then it will be described as an ion. The third shell will not exist again because the electron there has been given away. Thus, the sodium ion is going to have a smaller atomic radius because its size has been reduced. This implies that the sodium ion will have a smaller radius than the sodium atom.

mixer [17]2 years ago
3 0
Its atomic radius increases because there is less electron shielding after the sodium loses one e-.  Sodium is a nonmetal which means it forms an anion. Anions always increase from their original atomic radius
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%yield = 88.5%

<h3>Further explanation</h3>

Given

Reaction

Cu(s) + 2 AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s)

Required

The percent yield

Solution

mol AgNO₃(MW=169,87 g/mol) :

= mass : MW

= 127 : 169.87

= 0.748

mol Ag from equation :

= 2/2 x mol AgNO₃

= 2/2 x 0.748

= 0.748

Mass Ag (theoretical) :

= mol x Ar Ag

= 0.748 x 108

= 80.784

% yield = (actual/theoretical) x 100%

%yield = 71.5/80.784 x 100%

<em>%yield = 88.5%</em>

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2 years ago
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Explanation:

m=5g

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4 0
3 years ago
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Papessa [141]

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Explanation: I took the test, hope it helps.

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Answer:

The answer is "The First choice".

Explanation:

The whole question can be found in the file attached.

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Answer:

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Explanation:

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Read 2 more answers
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