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Nonamiya [84]
3 years ago
6

At room temperature, 20ÁC, water (H2O) is a liquid and oxygen (O2) is a gas. Based on kinetic molecular theory, which answer bes

t describes the states of the two fluids?
Chemistry
1 answer:
vaieri [72.5K]3 years ago
6 0
<span>Water molecules have a lower boiling temperature than oxygen molecules, so at room temperature they exist as a liquid rather than a gas.
hope it helps
</span>
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A sample of an unknown metal has a mass of 58.932g. it has been heated to 101.00 degrees C, then dropped quickly into 45.20 mL o
yaroslaw [1]
<h3>Answer:</h3>

0.111 J/g°C

<h3>Explanation:</h3>

We are given;

  • Mass of the unknown metal sample as 58.932 g
  • Initial temperature of the metal sample as 101°C
  • Final temperature of metal is 23.68 °C
  • Volume of pure water = 45.2 mL

But, density of pure water = 1 g/mL

  • Therefore; mass of pure water is 45.2 g
  • Initial temperature of water = 21°C
  • Final temperature of water is 23.68 °C
  • Specific heat capacity of water = 4.184 J/g°C

We are required to determine the specific heat of the metal;

<h3>Step 1: Calculate the amount of heat gained by pure water</h3>

Q = m × c × ΔT

For water, ΔT = 23.68 °C - 21° C

                       = 2.68 °C

Thus;

Q = 45.2 g × 4.184 J/g°C × 2.68°C

    = 506.833 Joules

<h3>Step 2: Heat released by the unknown metal sample</h3>

We know that, Q =  m × c × ΔT

For the unknown metal, ΔT = 101° C - 23.68 °C

                                              = 77.32°C

Assuming the specific heat capacity of the unknown metal is c

Then;

Q = 58.932 g × c × 77.32°C

   = 4556.62c Joules

<h3>Step 3: Calculate the specific heat capacity of the unknown metal sample</h3>
  • We know that, the heat released by the unknown metal sample is equal to the heat gained by the water.
  • Therefore;

4556.62c Joules = 506.833 Joules

c = 506.833 ÷4556.62

  = 0.111 J/g°C

Thus, the specific heat capacity of the unknown metal is 0.111 J/g°C

8 0
3 years ago
What is the final concentration of cl- ion when 250 ml of 0.20 m cacl2 solution is mixed with 250 ml of 0.40 m kcl solution? (as
serious [3.7K]

CaCl2 and KCl are both salts which dissociate in water when dissolved. Assuming that the dissolution of the two salts are 100 percent, the half reactions are:

<span>CaCl2 ---> Ca2+  +  2 Cl-</span>

KCl ---> K+ + Cl-

Therefore the total Cl- ion concentration would be coming from both salts. First, we calculate the Cl- from each salt by using stoichiometric ratio:

Cl- from CaCl2 = (0.2 moles CaCl2/ L) (0.25 L) (2 moles Cl / 1 mole CaCl2)

Cl- from CaCl2 = 0.1 moles

 

Cl- from KCl = (0.4 moles KCl/ L) (0.25 L) (1 mole Cl / 1 mole KCl)

Cl- from KCl = 0.1 moles

 

Therefore the final concentration of Cl- in the solution mixture is:

Cl- = (0.1 moles + 0.1 moles) / (0.25 L + 0.25 L)

Cl- = 0.2 moles / 0.5 moles

<span>Cl- = 0.4 moles             (ANSWER)</span>

6 0
3 years ago
How can you separate sand and sugar?
satela [25.4K]

Answer:

1)Filtration to remove sand

2)Evaporation to obtain sugar

Explanation:

Add water to the mixture and mix,sugar will dissolve.

Filter out the sand.

Evaporate the remaining solution to obtain the sugar.

7 0
3 years ago
When the temperature of a substance decreases to the substance's freezing point, the substance will begin to change from
Thepotemich [5.8K]

When the temperature of a substance decreases to the substance's freezing point, the substance will begin to change from a liquid  to a solid.

4 0
3 years ago
1.
Ede4ka [16]

Answer:

A.

Explanation:

Miners were happy due to the result of the gold rush. they labored very hard for very little profit. Working in the Yukon Territory was not safe. To reach it, the ground had to be dug. Then the dirt had to be removed to get the gold.

In paragraph 2, what does the phrase "miners of all shapes and sizes" mean that many people were invited. This included food, clothing, transportation equipment, etc.

8 0
3 years ago
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