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3 years ago

Equation of a line that best fits the points (-4,10)(-1,5) (2,-1) (3,-6) (5,-7)

Mathematics

1 answer:

Slav-nsk [51]3 years ago

8 0

Answer:

-2.02+2.22=trendline

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Find the period of the graph

olya-2409 [2.1K]

Answer:

240 degrees

Step-by-step explanation:

Looking at the graph we can see that the first peak is at -30 degrees and the second peak is at 210 degrees.

210 - (-30) = 210 + 30 = 240

5 0

3 years ago

I need help with no.7

ziro4ka [17]

Answer:

(a) 315°

(b) 3°

Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

The bearing of P from R is 180° different from the bearing of R from P it will be ...

135° +180° = 315° . . . . bearing of P from R

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

315° +48° = 363°, or 3° . . . . bearing of Q from R

The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

180° -48° -55° = 77°

The bearing of Q from P is 77° less than the bearing of R from P, so is ...

135° -77° = 58°

As above, the reverse bearing from Q to P is ...

58° +180° = 238° . . . . bearing of P from Q

8 0

2 years ago

GIVING 10 POINTS ANSWER ASAP PLEASE

Irina18 [472]

Answer:

the answer is n, 225 so u can use another app to make sure u find ur answer

8 0

3 years ago

What is the approximate distance between the points (-3,-4)(-8,1) on a coordinate grid?

Alex

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-3}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{-8}~,~\stackrel{y_2}{1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[-8-(-3)]^2+[1-(-4)]^2}\implies d=\sqrt{(-8+3)^2+(1+4)^2} \\\\\\ d=\sqrt{25+25}\implies d=\sqrt{50}\implies d\approx 7.071$

3 0

3 years ago

the length of a rectangle is 3 units shorter than one -third of the width, x. Which expression represents the perimeter of the r

Mariana [72]

Answer:

A) $\frac{8}{3} x - 6$

Step-by-step explanation:

Let the width of the rectangle be x units.

$\therefore \: length \: of \: rectangle = \frac{1}{3} x - 3 \\ Perimeter \: of \: rectangle = 2(l + w) \\ = 2 \bigg( \frac{1}{3} x - 3 + x \bigg)\\ = 2 \bigg( x + \frac{1}{3} x - 3 \bigg)\\ = 2 \bigg( \frac{3x + x}{3} - 3 \bigg)\\ = 2 \bigg( \frac{4x}{3} - 3 \bigg) \\ = 2 \bigg( \frac{4x}{3} - 3 \bigg) \\ = \frac{2 \times 4x}{3} -2 \times 3 \\ \purple{ \bold{{Perimeter \: of \: rectangle = \frac{8}{3} x - 6}}}$

8 0

3 years ago