How wide in m is a single slit that produces its first minimum for 631-nm light at an angle of 12. 0°? m
1 answer:
The single slit is 3.34 * m wide .
In the single-slit diffraction experiment, we can observe the bending phenomenon of light or diffraction that causes light from a coherent source to interfere with itself and produce a distinctive pattern on the screen called the diffraction pattern.
Diffraction is evident when the sources are small enough that they are relatively the size of the wavelength of light.
Fringe width is defined as the distance between any two consecutive bright or dark fringes.
Using the formula ,
nλ = a sin θ
a = nλ /sin θ
a = (1) (631 * ) / sin (12)
a = 3.34 * m
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Answer:
Solution given:
frequency[f]=60,500,000Hz
velocity[V]=300,000,000m/s
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wave length=
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Option A.4.96m
Answer:
The tension in the left side string = 17.21 N
The tension in the right side string = F = 27.3 N
Explanation:
Given that
F= 27.3 N
M= 1.43 kg ,r= 0.0792 m
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T- mg = ma
T- 0.7 x 10 = 0.7 a ----------1
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Form equation 1 and 2
a= 1.42 T - 10 m/s²
a = 1.42 ( 27.3 - T) m/s²
1.42 T - 10 = 38.9 - 1.42 T
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