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zlopas [31]
3 years ago
6

If a truck weighs 18,000 N and it’s tires are inflated to a pressure of 190 kPa how large is the area of the trucks tires that a

re in contact with the ground
Physics
1 answer:
Mamont248 [21]3 years ago
4 0

0.095m²

Explanation:

Given parameters;

Weight of truck = 18000N

Pressure = 190kPa or 190000Pa

Unknown:

Area of truck tires = ?

Solution:

Pressure is given as the force per unit area of a substance:

            Pressure = \frac{force }{Area}

  Since Area is the unknown, we make it the subject of the expression;

            Area = \frac{force }{pressure}

                     =\frac{18000}{190000}

                     =  0.095m²

Learn more:

Pressure brainly.com/question/7882867

#learnwithBrainly

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Two balls have their centers 2.0 m apart. One ball has a mass of m1 = 7.9 kg. The other has a mass of m2 = 6.1 kg. What is the g
maks197457 [2]

Answer:

3.036×10⁻¹⁰ N

Explanation:

From newton's law of universal gravitation,

F = Gm1m2/r² .............................. Equation 1

Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.

G = gravitational constant

Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²

Substituting into equation 1

F = 6.67×10⁻¹¹×7.9×6.1/2²

F = 321.427×10⁻¹¹/4

F = 30.36×10⁻¹¹

F = 3.036×10⁻¹⁰ N

Hence the force between the balls = 3.036×10⁻¹⁰ N

8 0
3 years ago
A car traveling at 23m/s starts to decelerate steadily. It comes to a complete stop in 7 seconds. What is the acceleration?
Lena [83]

The car has an initial velocity v_0 of 23 m/s and a final velocity v of 0 m/s. Recall that for constant acceleration,

v=v_0+at

The car stops in 7 s, so the acceleration is

0\,\dfrac{\mathrm m}{\mathrm s}=23\,\dfrac{\mathrm m}{\mathrm s}+a(7\,\mathrm s)

\implies a\approx-3.29\,\dfrac{\mathrm m}{\mathrm s^2}

7 0
3 years ago
Using software, a simulation of a javelin being thrown both on Earth and on the moon is created. In both cases, the velocity and
mario62 [17]

Horizontal distance covered by a projectile is X = Vix *T

where Vix is the initial horizontal component of velocity and T is time taken by the projectile

Vix = ViCos theta

In question they said that initial velocity and angle is same on earth and moon

so Vix would remains same

now let's see about time taken T

time taken to reach the highest point

Vfy = Viy +gt

at highest point vertical velocity become zero so Vfy =0

0 = Vi Sin theta + gt

t = Vi Sintheta /g

Total time taken to land will be twice of that

On earth

Te= 2t

Te = 2Sinθ/g

on moon g is one-sixth of g(earth)

Tm = 2Sinθ/(g/6)

Tm = 6(2Sinθ/g)

Tm = 6Te

so total time taken by the projectile on moon will be six times the time taken on earth

From first equation X = Vix*T

we can see that X will also be 6 times on moon than earth

so projectile will cover 6 times distance on moon than on earth

4 0
3 years ago
Read 2 more answers
Which microbes can be Eukaryotic? A. bacteria B. virus C. protists D. fungi
MissTica
Hey there,

Question : Which microbes can be Eukaryotic?

Answer : A, Bacteria

Hope this helps :D

<em>~Top♥</em>


3 0
3 years ago
Read 2 more answers
Bats have poor vision and use echo-location to find their way.The frequency produced by bats is 100kHz. If the speed of the soun
irga5000 [103]

The distance covered is 25.9 m.

<h3>How deep is the cave?</h3>

We know that the speed of sound refers to the speed with which an sound moves in an object.

Given that;

speed of sound = 345m/s

Time taken =  0.15s

We know that;

v = 2d/t

v = speed of sound

d = distance

t = time taken

vt = 2d

d = vt/2

d = 345m/s *  0.15s/2

d = 25.9 m

Learn more about speed of sound:brainly.com/question/15137350

#SPJ1

5 0
2 years ago
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