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zlopas [31]
3 years ago
6

If a truck weighs 18,000 N and it’s tires are inflated to a pressure of 190 kPa how large is the area of the trucks tires that a

re in contact with the ground
Physics
1 answer:
Mamont248 [21]3 years ago
4 0

0.095m²

Explanation:

Given parameters;

Weight of truck = 18000N

Pressure = 190kPa or 190000Pa

Unknown:

Area of truck tires = ?

Solution:

Pressure is given as the force per unit area of a substance:

            Pressure = \frac{force }{Area}

  Since Area is the unknown, we make it the subject of the expression;

            Area = \frac{force }{pressure}

                     =\frac{18000}{190000}

                     =  0.095m²

Learn more:

Pressure brainly.com/question/7882867

#learnwithBrainly

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Acceleration is the magnitude of average velocity.​
lina2011 [118]

Answer:

false

Explanation:

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4 0
3 years ago
A silver wire has a cross sectional area a = 2.0 mm2. a total of 9.4 × 1018 electrons pass through the wire in 3.0 s. the conduc
marta [7]
This problem uses the relationships among current I, current density J, and drift speed vd. We are given the total of electrons that pass through the wire in t = 3s and the area A, so we use the following equation to to find vd, from J and the known electron density n, so: 

v_{d} =  \frac{J}{n\left | q \right |}

<span>The current I is any motion of charge from one region to another, so this is given by:

</span>I = \frac{\Delta Q}{\Delta t} = \frac{9.4x1018electrons}{3s} = 3189.73(A)

The magnitude of the current density is:

J = \frac{I}{A} = \frac{3189.73}{2x10^{-6}} = 1594.86(A/m^{2})

Being:

A=2mm^{2} = 2x10^{-6}m^{2}
<span>
Finally, for the drift velocity magnitude vd, we find:

</span>v_{d} = \frac{1594.86}{5.8x1028\left |1.60x10^{-19}|\right } = 1.67x10^{18}(m/s)

Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
6 0
3 years ago
If the distance to a point source of sound is doubled, by what multiplicative factor does the intensity change?
alina1380 [7]

If the distance to a point source of sound is doubled, by a multiplicative factor of 4, the intensity changes.

Intensity of sound is the sound which is perpendicular to sound wave propogation per unit area. It is dependent on the Surface of source sound.

Intensity is the Power per unit area. Its SI unit is Watt/m².

As we move away from a source of sound, the sound starts to diminish. This is due to the decreasing sound intensity with distance.

It can also be understood by the fact that on increasing distance, the Power radiated by the source spreads over a larger area. Hence, the Intensity decreases gradually.

Since, Intensity is proportional to the square of the distance.

Hence, on doubling the distance, Intensity reduces to one fourth of the initial intensity or reduces by a multiplicative factor of 4.

Learn more about Intensity here, brainly.com/question/17583145

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Find the volume of a cube measeuring 5 cm on each side
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Timed plz hurry
puteri [66]

Answer:

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Explanation:

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