If a truck weighs 18,000 N and it’s tires are inflated to a pressure of 190 kPa how large is the area of the trucks tires that a
1 answer:
0.095m²
Explanation:
Given parameters;
Weight of truck = 18000N
Pressure = 190kPa or 190000Pa
Unknown:
Area of truck tires = ?
Solution:
Pressure is given as the force per unit area of a substance:
Pressure =
Since Area is the unknown, we make it the subject of the expression;
Area =
=
= 0.095m²
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Answer:
Density (φ) = 0,8827 Kg/L
Specific weight (Ws) = 8,65 N/L
Specific gravity (Gs) = 0,8827 (without unit)
Explanation:
The density formula: φ =
I know the mass "m", I need to find out the volume of the cylinder (V)
V = π* r²*h
The radius "r" is equal to half the diameter (150mm) = 75mm
Now I can find out the density (φ)
φ = = 0,8827 Kg/L
The specific weight (Ws) is the relationship between the weight of substance (oil) and its volume. We apply the following formula:
Ws = φ*g
(g = gravity = 9,8 m/s²)
Finally, specific gravity (Gs) is the ratio between the density of a substance (oil) "φ(o)" and the density of water "φ(w)" :
Gs = φ(o) / φ(w)
(φ(w) = 1 Kg/L
Hope this can help you !!
Answer: Option (b) is the correct answer.
Explanation:
The given data is as follows.
F = N
g = 9.8 m/s
radius =
= = 15 cm = 0.15 m (as 1 m = 100 cm)
Formula to calculate depth is as follows.
F =
or, h =
h =
= 751 m
Thus, we can conclude that the maximum depth in a lake to which the submarine can go without damaging the window is closest 750 m.