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Ray Of Light [21]
3 years ago
5

Part e a small toy cart equipped with a spring bumper rolls toward a wall with a speed of v. the cart rebounds from the wall, wi

th the same speed v. the sketch below shows the initial velocity vector v⃗ i, final velocity vector v⃗ f, and the initial momentum vector p⃗ i. using the initial momentum vector as a basis, draw the change in momentum vector δp⃗ for the cart. you can obtain each vector's length and orientation by clicking on it to select it.

Physics
1 answer:
jeka943 years ago
5 0

Answer:

Δp = -2 p₀

Explanation:

The momentum is defined by

         p = m v

In this case we write the initial and final momentum, we take as positive the direction towards the wall.

         p₀ = m v

         p_f = m (-v)

the negative sign is because the car is bouncing off the wall

the change of the moment is

       Δp = p_f - p₀

        Δp = - m v - m v

        Δp = -2 mv

        Δp = -2 p₀

we see that the change of moment is twice the moment, in the attachment we can see the vectors of these changes and the sign indicates the direction of the change at the moment

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A spacecraft has a momentum of 20,000 kg-m/s, and a mass of 250 kg. What is the magnitude of its velocity?
Harlamova29_29 [7]

Answer:

<h2>A. 80 m/s </h2>

Explanation:

The velocity of the spacecraft can be found by using the formula

v =  \frac{p}{m}  \\

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From the question we have

v =  \frac{20000}{250}  =  \frac{2000}{25}  \\

We have the final answer as

<h3>80 m/s</h3>

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Answer:

λ = 5.65m

Explanation:

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δ= \sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }

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δ= \sqrt{6749}-\sqrt{5429}

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δ= 8.47

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δ= 8.47

8.47 = \frac{3*lamda}{2}

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Hi! :)


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