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3 years ago

Which shape of ice melts the fastest? cylinder, cube, or rectangular cube?

Chemistry

2 answers:

Gnoma [55]3 years ago

3 0

They will melt at the same rate because they contain the same matter
hope this helps and good luck on your project!!!!

OlgaM077 [116]3 years ago

3 0

The cube will because it's smaller then the other cubes and they don't all contain the same matter because some are small, longer, and wider.

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A 0.600-L sample of a 3.75M solution of potassium iodide (KI) contains what mass of KI?

Sergeeva-Olga [200]

the molarity of a solution made by dissolving 5.67 g of potassium chloride in enough water to make 100.0 mL of solution.

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2 years ago

Suppose the total volume of sand on the beach is 1,278m. What will the volume be after 24 hours of erosion?

agasfer [191]

Answer:

Let's assume that the erosion rate is "X/hour". The total volume of sand on a beach after 24 hours would be,

= total sand volume - (erosion rate per hour * 24)

= 1,278m - (X/hour * day)

Explanation:

Now assume that the erosion rate is 1 m per hour. Therefore, in 24 hours would be,

= 1,278m - (1/hour * 24)

= 1,278 - 24

= 1254 m.

5 0

3 years ago

How long will it take for a 40.0 gram sample of I-131 (half-life = 8.4 days) to decay to 1/16 its original mass?

Shtirlitz [24]

Answer:

42 days

Explanation:

Half life = 8.4 days

Starting mass = 40.0 g

Time = ?

Final Mass = 1/16 * 40 = 2.5 g

First Half life;

Remaining mass = 40 / 2 = 20g

Second Half life;

Remaining mass = 20 / 2 = 10g

Third Half life;

Remaining mass = 10 / 2 = 5g

Fourth Half life;

Remaining mass = 5 / 2 = 2.5g

Time = Number of half lives * Duration of half life = 5 * 8.4 = 42 days

6 0

2 years ago

The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.

atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M

Explanation:

The photodissociation of ozone by UV light is given by:

O₃ + hν → O₂ + O (1)

The first-order reaction of the equation (1) is:

$rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t}$ (2)

where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration

We can get the following expression of the first-order integrated law of the reaction (1), by resolving the equation (2):

$[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt}$ (3)

where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration

We can calculate the initial ozone concentration using equation (3):

$[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M$

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!

3 0

3 years ago

A golf ball with a mass of 46 grams will accelerate five times as fast as a

ELEN [110]

Answer:

Newtons first law

Explanation:

focre=mass x acceleration

6 0

2 years ago

Read 2 more answers