3 years ago

How much heat is required to boil 78.5 gg of water at its boiling point?

1 answer:

NISA [10]3 years ago

8 0

Answer:

206 kj of heat is required to boil 78.5 kg of water at its boiling point

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Sedbober [7]

<u>Answer:</u> The energy of one photon of the given light is $3.79\times 10^{-19}J$

<u>Explanation:</u>

To calculate the energy of one photon, we use Planck's equation, which is:

$E=\frac{hc}{\lambda}$

where,

$\lambda$ = wavelength of light = $525nm=5.25\times 10^{-7}m$ (Conversion factor: $1m=10^9nm$ )

h = Planck's constant = $6.625\times 10^{-34}J.s$

c = speed of light = $3\times 10^8m/s$

Putting values in above equation, we get:

$E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J$

Hence, the energy of one photon of the given light is $3.79\times 10^{-19}J$

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3 years ago