How much heat is required to boil 78.5 gg of water at its boiling point?
1 answer:
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Solution :
Given :
Amount of anserine solution = 0.200 M
pH value is = 7.20
Preparation of 0.04 M solution of anserine from the 0.2 M solution.
0.2 M x = 0.04 M x 1000 ml
= 200 ml
So the 200 ml of 0.2 M anserine solution is required to prepare0.04 M of anserine.
0.1 M x = 0.04 x 1000 ml
= 400 ml
Therefore, 400 ml of HCl is needed.
Answer:
3441.6 grams.
Explanation:
2 O₃ → 3 O₂
First we <u>convert 71.7 moles of ozone (O₃) into moles of oxygen gas (O₂)</u>, using the <em>stoichiometric coefficients</em> of the reation:
71.7 mol O₃ * = 107.55 mol O₂
Then we <u>convert 107.55 moles of O₂ into grams</u>, using the <em>molar mass of O₂</em>:
107.55 mol * 32 g/mol = 3441.6 g