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wlad13 [49]
2 years ago
15

How much heat is required to boil 78.5 gg of water at its boiling point?

Chemistry
1 answer:
NISA [10]2 years ago
8 0

Answer:

206 kj of heat is required to boil 78.5 kg of water at its boiling point

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EXPLAIN How did energy change form in the calorimeter lab?
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Answer:

Chemical energy is converted into thermal and mechanical energy while kinetic energy into potential energy.

Explanation:

As the breakdown of food started, the chemical energy present in the food substances converted into thermal energy and mechanical energy. Thermal or heat energy is used to maintain the body's temperature while mechanical energy is used in other activities such as movement of muscles. Kinetic energy is also converted into potential energy when the object moves from top of a place such as hill.

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Explanation:

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An object has a mass of 18.4g and a volume of 11.2 ml what is the density
DENIUS [597]

Density=mass/volume

Density=18.4g/11.2ml

Density=1.64

Just make sure you include the unit of measurement with your answer.

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Type the correct answer in each box.
BARSIC [14]

Answer:

mg3n2 and cacl3 hope it helps

4 0
3 years ago
Mass in grams of 6.023×1023 atom of Ca​
Mademuasel [1]

Answer:

\boxed {\boxed {\sf 40.08 \ grams}}

Explanation:

First, find the molar mass of calcium (Ca). This can be found on the Periodic Table.

  • 40.08 g/mol

Next, find the number of moles.

Avogadro's Number tells us the number of atoms in one mole.

  • It is 6.023*10²³

Therefore, there are 6.023*10²³ atoms in 1 mole.

We have 6.023*10²³ atoms of calcium, so it must also be 1 mole of calcium.

Finally, find the mass. Set up a proportion using the molar mass of calcium.

1 \ mol \ Ca * \frac{40.09 \ g}{1 \ mol \ Ca}

Multiply. The moles (mol Ca) will cancel.

1 * 40.08 \ g

40.08 \ g

There are <u>40.08 grams </u>in 6.023*10²³ atoms of calcium.

5 0
2 years ago
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