a. 0.137
b. 0.0274
c. 1.5892 g
d. 0.1781
e. 5.6992 g
<h3>Further explanation</h3>
Given
Reaction
2 C4H10 + 13O2 -------> 8CO2 + 10H2O
2.46 g of water
Required
moles and mass
Solution
a. moles of water :
2.46 g : 18 g/mol = 0.137
b. moles of butane :
= 2/10 x mol water
= 2/10 x 0.137
= 0.0274
c. mass of butane :
= 0.0274 x 58 g/mol
= 1.5892 g
d. moles of oxygen :
= 13/2 x mol butane
= 13/2 x 0.0274
= 0.1781
e. mass of oxygen :
= 0.1781 x 32 g/mol
= 5.6992 g
Over the northern parts of the Pacific Ocean, the Maritime Polar air mass exists. This means that the air mass likely to be over the northern parts of the Pacific Ocean would be wet and cold.
The balanced reaction is: 2Mo+3O2>2MoO3
$315 is your total cost of all
rent = 45 * numbers of days
d = numbers of days
45d
2 days free
45(d-2) = 315
Divide 45 to both sides
d-2 = 7
Add 2 to both sides
d = 9
So he rented for 9 days.
Hope this helps
The answer would be: carbon dioxide(CO2) and water (H2O).
The combustion of methane gas family typically will result in carbon dioxide and water. It will need many oxygen gases to do the combustion. The reaction equation would be:
<span>C4H8(l) + 6O2(g) ==> 4CO2 + 4H2O</span>
