I believe the answer is 65.254%
Answer:
- The abundance of 107Ag is 51.5%.
- The abundance of 109Ag is 48.5%.
Explanation:
The <em>average atomic mass</em> of silver can be expressed as:
107.87 = 106.90 * A1 + 108.90 * A2
Where A1 is the abundance of 107Ag and A2 of 109Ag.
Assuming those two isotopes are the only one stables, we can use the equation:
A1 + A2 = 1.0
So now we have a system of two equations with two unknowns, and what's left is algebra.
First we<u> use the second equation to express A1 in terms of A2</u>:
A1 = 1.0 - A2
We <u>replace A1 in the first equation</u>:
107.87 = 106.90 * A1 + 108.90 * A2
107.87 = 106.90 * (1.0-A2) + 108.90 * A2
107.87 = 106.90 - 106.90*A2 + 108.90*A2
107.87 = 106.90 + 2*A2
2*A2 = 0.97
A2 = 0.485
So the abundance of 109Ag is (0.485*100%) 48.5%.
We <u>use the value of A2 to calculate A1 in the second equation</u>:
A1 + A2 = 1.0
A1 + 0.485 = 1.0
A1 = 0.515
So the abundance of 107Ag is 51.5%.
Carbohydrates are classified in three major categories depending upon the number of sub units joining to form them. These are,
Monosaccharides
Oligosaccharides
Polysachharides
The simplest single units are monosaccharides, if units are ranging between two and twenty they are called oligosaccharides and above twenty joining units they are called polysachharides.
Result:
<span>The proper name for a carbohydrate polymer with 2 subunits is called Oligosachharide in general and Disaccharide in specific.</span>
Well, black would absorb the light, if that is in some way what you mean
Answer is: Sb(g) → Sb⁺(g) + e⁻.
Neutral atom in gas state lose one valence electron and become cation with postive charge.
<span>The first ionisation energy is the energy required to remove one mole of the valence electrons from one mole of gaseous atoms to produce one mole of gaseous ions each with a charge of 1+.</span>
<span>Most metals have strong
metallic bond, because strong electrostatic attractive force
between valence electrons (metals usually
have low ionization energy and lose electrons easy) and positively
charged metal ions.
</span>
