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AleksAgata [21]
2 years ago
10

Why is the 6 m naoh solution diluted before titrating the vinegar sample? How might your results be affected if you used the 6 m

solution rather than the 0. 3 m naoh?
Chemistry
1 answer:
Agata [3.3K]2 years ago
5 0

The 6 M solution NaOH solution diluted before titrating the vinegar sample because pH at the equivalence point changes very rapidly . It is very useful to have dilution solution , so that number of moles that are transferred per drop of the solution is low . So, pH change smaller amount per drop. Having more dilute solution also allows the titration to use volume that is easier to work with.

If you used the 6 M solution was used then the volume required for titration would go down by a factor of 6/0.3 = 20

This means that if a titration took 20ml of the 0.3 M solution then it would take 1ml of the NaOH solution.

Titration consists of adding a controlled and known amount of standard solution with an unknown until the reaction to be complete.

Learn more about NaOH solution

brainly.com/question/14296114

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What volume of 1.50 M KBr is fromed ,using 15.6 mL of concentrated KBr with a molarity of 9.65 M?
Montano1993 [528]

Answer:

100.4mL

Explanation:

Using the following formula:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information in this question,

C1 = 1.50M

V1 = ?

C2 = 9.65 M

V2 = 15.6 mL

Using C1V1 = C2V2

V1 = C2V2/C1

V1 = (9.65 × 15.6) ÷ 1.5

V1 = 150.54 ÷ 1.5

V1 = 100.36 mL

Approximately, V1 = 100.4mL

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3 years ago
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solong [7]

Answer:

H

Explanation:

Hydrogen is a nonmetal love:)

3 0
3 years ago
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True or False. Ecosystems are always very large and cover a large amount of land.
Rainbow [258]

False is the answer

3 0
3 years ago
A sample of gas (1.9 mol) is in a flask at 21 °C and 697 mmHg. The flask is opened and more gas is added to the flask. The new p
mariarad [96]

Answer:

The new moles of the gas in the flask is 2.13 moles.

Explanation:

Given;

number of moles of gas, n = 1.9 mol

temperature of the gas, T = 21 °C  = 21 + 273 = 294 K

pressure of gas, P = 697 mmHg

volume of gas, V = ?

Apply ideal gas law;

PV = nRT

Where;

R is gas constant, = 62.363 mmHg.L / mol. K

V = nRT / P

V = (1.9 x 62.363 x 294) / 697

V = 49.98 L

New pressure of the gas, P = 795 mmHg

New temperature of the gas, T = 26 °C = 273 + 26 = 299 K

New moles of the gas, n = ?

Volume of the gas is constant because volume of the flask is the same when more gas was added.

n = PV / RT

n = (795 x 49.98) / (62.363 x 299)

n = 2.13 moles

Therefore, the new moles of the gas in the flask is 2.13 moles.

4 0
4 years ago
If a helium balloon is put into a hot oven. What happens to the volume of the balloon?
AveGali [126]

Answer:

What about hot air balloons? They work by similar principles. If you heat up a gas it expands. In the case of a hot air balloon, when the gas inside the balloon expands the extra gas is pushed out the bottom of the balloon, meaning that there are fewer atoms inside the balloon, meaning that the air in the balloon is lighter than the air outside the balloon.

The amount of lifting power is controlled by how hot the air is. If you heat the air inside the balloon 100 degrees F hotter than the outside air temperature, then the air inside the balloon will be about 25 percent lighter than the air outside the balloon. So a cubic foot of air weighs about 35 grams at 32 degrees F. A cubic foot of hot air at 132 degrees F will weigh 25 percent less, or about 26.5 grams. The difference is 8.5 grams or so. So a hot air balloon has to be much bigger to support the same weight, but it will float because hotter air is lighter than cooler air.

Explanation:

The amount of lifting power

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