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3 years ago

What volume of 1.50 M KBr is fromed ,using 15.6 mL of concentrated KBr with a molarity of 9.65 M?

Chemistry

1 answer:

Montano1993 [528]3 years ago

4 0

Answer:

100.4mL

Explanation:

Using the following formula:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information in this question,

C1 = 1.50M

V1 = ?

C2 = 9.65 M

V2 = 15.6 mL

Using C1V1 = C2V2

V1 = C2V2/C1

V1 = (9.65 × 15.6) ÷ 1.5

V1 = 150.54 ÷ 1.5

V1 = 100.36 mL

Approximately, V1 = 100.4mL

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2 years ago

Two samples of potassium iodide are decomposed into their constituent elements. The first sample produced 13.0g of potassium and

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Answer:

79.43kg

Explanation:

To adequately solve this problem, we should know the law of constant composition. This is a pointer to the fact that no matter the type of sample, the percentage compositions of potassium and iodine still remains the same. We can use these masses to get a formula and we would know the percentage compositions in whatever mass we are dealing with.

First of all, we add the masses in the first sample. 13 + 42.3 = 55.3

Hence, the percentage composition of the potassium is 13/55.3 * 100 = 23.51%

The percentage composition of the iodine is = 100 - 23.51 = 76.49%

Now, we need to get the formula of the compound. We can get this by dividing the percentage compositions with the atomic masses. The atomic mass of potassium and iodine is 39 and 127 respectively.

Potassium = 23.51/39 =0.603

Iodine = 76.49/127 = 0.602

We then divide by the smaller value to get the formula and this shoes our formula is KI

We can see they have a ratio of 1 to 1, meaning one atom of potassium to one atom of iodine. This further confirms the percentage compositions of 23.5 to 76.5

Now to get the mass of iodine yielded, let us say the mass is xkg

This means x/(x + 24.4) * 100 = 76.5

100x = 76.5( x + 24.4)

100x = 76.5x + 1866.6

100x - 76.5x = 1866.6

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3 years ago

Is zinc a basic radical or acid radical?

lukranit [14]

Answer:

depends on the element it's reacting with..

Explanation:

if the another element requires less energy to loose electron then zinc will become negatively charged and hence becomes acidic radical..

normally if it is reacting with element with valency 4 and Atomic number less than it(Ti,Si,C) then it will lose electron and gain positive sign and henve becomes basic radical..

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