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WINSTONCH [101]
3 years ago
15

What volume of 1.50 M KBr is fromed ,using 15.6 mL of concentrated KBr with a molarity of 9.65 M?

Chemistry
1 answer:
Montano1993 [528]3 years ago
4 0

Answer:

100.4mL

Explanation:

Using the following formula:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information in this question,

C1 = 1.50M

V1 = ?

C2 = 9.65 M

V2 = 15.6 mL

Using C1V1 = C2V2

V1 = C2V2/C1

V1 = (9.65 × 15.6) ÷ 1.5

V1 = 150.54 ÷ 1.5

V1 = 100.36 mL

Approximately, V1 = 100.4mL

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Rank the elements b, be, n, c, and o in order of increasing first ionization energy. (use the appropriate <, =, or > symbo
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Be, B, C, N (going from smallest to biggest)
6 0
3 years ago
An average human being has about 5.0 L of blood in his or her body. If an average person were to eat 37.7 g of sugar (sucrose, ,
Viktor [21]

Answer: 0.0220275 M

Explanation:

So, we are given the following data or parameters which are going to help in solving this particular Question/problem.

=> Averagely, we have the volume = 5.0 L of blood in human body .

=> Mass of sugar eaten = 37.7 g of sugar (sucrose, 342.30 g/mol).

Therefore, the molarity of the blood sugar change can be calculated as below:

The molarity of the blood sugar change = (1/ volume) × mass/molar mass.

Thus, the molarity of the blood sugar change = (1/5) × 37.7/342.30 = 0.0220275 M.

6 0
2 years ago
If 185 mg of acetaminophen were obtained from a tablet containing 350 mg of acetamino- phen, what would be the weight percentage
Alex73 [517]

Percentage recovery gives us an idea of the amount of pure substance recovered after the chemical reaction. Percentage recovery can be more than 100 % or less than 100 %. Usually, in any experiment performed the weight percentage recovery will be less than 100. Percent recovery values greater than 100 show that the recovered compound is contaminated.

Amount of acetaminophen initially taken = 350 mg

Amount of acetaminophen obtained after recovery =185 mg

Weight percentage recovery =\frac{mass recovered}{mass originally taken}*100

                                                = \frac{185 mg}{350 mg}*100

                                               = 52.9%

8 0
3 years ago
If 0. 3 moles of H2O were produced, how many moles of carbon dioxide would also have been produced?
grigory [225]

In a chemical reaction, 0. 3 moles of H2O result in the production of 0.2 moles of CO2. Chemical reactions are the means through which one group of chemical compounds are changed into another.

Chemical reactions are typically defined as changes that only affect the positions of electrons in the formation and breakage of chemical bonds between atoms, with no change to the nuclei (i.e., no change to the elements present). These types of changes are often included in the term chemical reactions.

Number of moles Definition We utilize this enormous quantity to measure atoms. Additionally, it equals the 6.022* 10 23 atoms that make up 12 grammes of carbon-12, or atoms.

C2H6 + 7/2O2 = 2CO2 + 3H2O,

where moles(CO2)=(2*0,3)/3=0.2 mol,

and n(CO2)=(2*0,3)/3=n(H2O);

n(CO2)=n(CO2)=n(H2O).

Learn more about chemical reaction here

brainly.com/question/3461108

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4 0
10 months ago
Select all the correct locations.
NikAS [45]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

The land breeze arrow is correct

The rest are incorrect.

Warm air should 'rise' by the land

This air then moves towards the sea and cools down

The cool air would then sink

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

5 0
3 years ago
Read 2 more answers
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