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vodomira [7]
2 years ago
8

(a 2n - a n - 6) (a n + 8)

Mathematics
1 answer:
yawa3891 [41]2 years ago
6 0
Here
2an-an=an
then (an-6)(an+8)
=asqnsq+8an-6an+48
=asqnsq+2an+48answer



sq is square and first We should add or subtract like terms
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The length of a rectangle in centimeters is two more than thrice its width. a) Write an expression, in the simplest form, for th
Karo-lina-s [1.5K]

Answer:

Perimeter of the rectangle = 8 x +4

Length of the rectangle = 12 units.

Step-by-step explanation:

Let the width of the rectangle as 'x' units.

So, length of the rectangle is 2 more than 3 x.

We can set up expression for length as 3 x+2.

Now, perimeter is sum of all side lengths of the rectangle.

So, perimeter = x+x+3 x+2 +3 x+2

Combine like terms,

Perimeter = 8 x+4

Now, it is given perimeter is 36cm

So,

8 x+4=36

Subtract both sides 4

8 x=32

Divide both sides by 8

x=4

So, width of the rectangle =4

Length =3(4) +2=14

3 0
3 years ago
Solve the inequality and graph its solution...<br> 2x+4≥24
Dima020 [189]
X=10
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6 0
2 years ago
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There are 158 students registered for American History classes. There are twice as many students registered in second period as
Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

<em><u>Solution:</u></em>

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

<em><u>There are 158 students registered for American History classes.</u></em>

Therefore,

x + y + z = 158 ---------- eqn 1

<em><u>There are twice as many students registered in second period as first period</u></em>

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

<em><u>There are 10 less than three times as many students in third period as in first period</u></em>

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

x + 2x + 3x - 10 = 158

6x = 168

<h3>x = 28</h3>

<em><u>Substitute x = 28 in eqn 2</u></em>

y = 2(28)

<h3>y = 56</h3>

<em><u>Substitute x = 28 in eqn 3</u></em>

z = 3(28) - 10

z = 84 - 10

<h3>z = 74</h3>

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

5 0
2 years ago
What is the value of x?<br> (x + 40)<br> (3x)<br> O 20<br> R<br> O<br> O 35<br> O<br> O<br> ASAP
Natasha2012 [34]

Angles TRS and VRW are vertical angles, so we can set them equal to each other to get x:

x+40=3x

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20=x

So the value of x is 20

3 0
3 years ago
TAKE ANY UNMARKED BOWL OR GLASS AND FILL IT EXACTLY 3/5 FULL WITH WATER.
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Answer:

Take a glass, and fill it completely with water.

Now, pour that water in a marked bowl and measure how much water is in the bowl, that amount of water will be 100% of the total water that the glass can have.

Now you need to pour 3/5 of the water back in the glass, it is easier for water until the water in the bowl is exactly 2/5 of the initial amount.

You can do this as follows.

2/5 = 0.4 or 40% in percentage form.

Then if the amount of water in the marked bowl is A, the amount of water that must remain in the marked bowl is A*0.4

Then drop the water in the glass until the water in the marked bowl is the quantity that you found previously.

In this way, you can be sure that the glass is 3/5 full of water.

8 0
3 years ago
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