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3 years ago

Scientists are studying different jackets made for extremely cold, snowy weather. They are trying to find jackets

Chemistry

1 answer:

koban [17]3 years ago

8 0

Answer:

Which jacket traps the most heat.

Explanation:

I took the test

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How many molecules are in the quantities below.? 2.0 moles

matrenka [14]

Mole=number of molecules/6.02x10²³
mole=2
number of molecules= 2x6.02x10²³
number of molecules=12.04x10²³

5 0

3 years ago

At standard ambient temperature and pressure (SATP), a gas has density of 1.5328g/L. What is the molar mass of the gas?

Oksi-84 [34.3K]

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3 years ago

Use the following half-reactions to construct a voltaic cell:

velikii [3]

Answer: The correct answer is $3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V$

Explanation:

We are given:

$Cr^{3+}(aq.)+3e^-\rightarrow Cr(s);E^o=-0.73V\\\\Ag^+(aq.)+e^-\rightarrow Ag(s);E^o=+0.80V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.

Chromium will undergo oxidation reaction and will get oxidized.

The half reactions for the above cell is:

Oxidation half reaction: $Cr(s)\rightarrow Cr^{3+}+3e^-;E^o_{Cr^{3+}/Cr}=-0.73V$

Reduction half reaction: $Ag^{+}+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V$ ( × 3)

Net equation: $3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.80-(-0.73)=1.53V$

Hence, the correct answer is $3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V$

4 0

3 years ago

The half life of Radon-222 is 3.8 days. If you have a 90.0g sample of Radon-222 in the lab, how much will be left after 19 days?

statuscvo [17]

Answer:

half lives passed=5

given sample=90g

sample left=2.8125g

Explanation:

no. of half lives=total time/half life

no.=19days/3.8days

no.=5 days

after 5 half lives sample left=2.8125g

5 0

3 years ago

URGENT!!!!!!!!Which reaction takes place in a nuclear fission reactor?

ivolga24 [154]

Answer: The correct answer is Option d.

Explanation:

Nuclear fission reaction is defined as the reaction in which 1 heavier nuclei splits into two or more smaller nuclei.

As, nuclear fission reactors require a large amount of energy to split the nucleus, hence it is bombarded with a particle in order to star the reaction.

In a nuclear reaction, a large fissile atomic nucleus like Uranium-235 $(_{92}^{235}\textrm{U})$ or Plutonium-239 $(_{94}^{239}\textrm{Pu})$ when absorbs a neutron, it undergoes nuclear fission reaction.

Hence, in the given options, uranium-235 is absorbing a neutron. Therefore, the correct answer is Option d.

6 0

3 years ago

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