Answer:
pH value test can be used to demonstrate that NaOH is a stronger alkali than NH3
Explanation:
pH value test can be used to demonstrate that NaOH is a stronger alkali than NH3. This is done by measuring the same volume of equal concentration of hydroxide and ammonia. A glass rod was dipped into 0.2 M of sodium hydroxide and 0.2 M of ammonia, each drop of solution was then placed on a pH paper matched with a color chart and the pH value was recorded.
The result showed that sodium hydroxide being a strong alkali would dissociate completely in aqueous solution thereby having a higher pH while ammonia would dissociate slightly/partially in aqueous solution thereby having a lower pH value
Answer: Al(ClO3)3 molecular weight.
Explanation:
81.9 % is the percent yield of reaction of zinc with iodine producing ZnI2.
Explanation:
Balanced chemical equation for the reaction:
Zn + I2 ⇒ ZnI2
Data given:
mass of sample zinc = 129 grams
mass of ZnI2 formed = 510.6 grams (actual yield)
number of moles = 
number of moles of zinc = 
= 1.97 moles
from stoichiometry
1 mole of Zn reacts to form 1 mole of ZnI2
1.97 moles of Zn will form 1.97 moles of ZnI2
atomic mass of ZnI2 = 319.22 grams/mole
mass of ZnI2 formed = 628.86 grams (theoretical yield)
% yield = 
x100 equation 1
from the reaction,
Putting the values in equation 1
% yield = 
x 100
= 81.19 % is the % yield.
Answer:
The value of Kc is 660 (Option E) is correct
Explanation:
Step 1: Data given
Kp = 27
Temperature = 25.0 °C
Step 2: The balanced equation
2 NO(g) + Br2(g) ⇄ 2 NOBr(g)
Step 3: Calculate Kc
Kp = Kc * (RT)^Δn
⇒ with Kp = 27
⇒ with Kc = TO BE DETERMINED
⇒ with R = the gas constant = 0.08206 L*atm/mol*K
⇒ with T = The temperature = 25 °C = 298 K
⇒ Δn = the difference in moles = -1
27 = Kc * (0.08206*298)^-1
Kc = 660
The value of Kc is 660 (Option E) is correct
