Question

Titanium's specific heat capacity is 0. 523 j/g*k. how many joules of heat are required to raise the temperature of 2. 50g of titanium from 65. 0°c to 600. 0°c?

Answer 1

The amount of heat required to raise the temperature is 706.05J.

To find the answer, we need to know more about the specific heat capacity.

How to find the heat required to raise the temperature?

• Specific heat can be defined as, the amount of heat needed to increase a substance's temperature by one degree for every gram.
• We have the expression for amount of heat required to raise the temperature from T1 to T2 as,

                                 Q=msΔT

• We have given with the following values,

                 $m=2.50g=2.50*10^{-3}kg\\s=0.523 J/gK=\frac{0.523}{10^{-3}} J/kgK=523J/kgK\\T_1=65^0C=338K\\T_2=600^0C=873K$

• Thus, the amount of heat required to raise the temperature is,

            $Q=2.5*10^{-3}*523*(873-333)=706.05 J$

Thus, we can conclude that, the amount of heat required to raise the temperature is 706.05J.

Learn more about the specific heat capacity here:

brainly.com/question/18798150

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