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IgorC [24]
3 years ago
6

If your weight is force created by gravity on your body, and therefore is the Earth pulling you down, what is the reaction force

?
Physics
1 answer:
IRISSAK [1]3 years ago
3 0

Answer:

The reaction force is the force exerted by your body on the earth pulling upwards.

Explanation:

This can be explained using Newton's third law of motion which states that if object A exerts  a force on object B, object B exerts a force of equal magnitude and opposite direction on object A. One characteristics of these force are that they act o 2 different bodies. In this example, the earth exerts a force on you. The Newton's reaction force would be you exerting a force of equal magnitude on the earth.

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(a) Are the radiating electric field lines around a charged particle straight lines when the particle is stationary?
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Answer:

Yes

Explanation:

(a)

Yes, the radiating electric field lines around a stationary charged particle are straight lines when the particle is stationary.

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4 years ago
6CO2 + 6H20 + (energy)
Studentka2010 [4]

Answer:6CO2 + 6H20 + (energy) → C6H12O6 + 6O2 Carbon dioxide + water + energy from light produces glucose and oxygen

Explanation:

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3 years ago
A 3,568 kg elephant is riding a bicycle at a speed of 43 m/s. Out of nowhere, a zebra runs out in the elephant's path and he mus
Katarina [22]

Answer:

3302 meters!

Explanation:

Wow!

The acceleration due to the stopping force of the brakes is given by Force/mass = 1000/3568 =.28m/s^-2

We will apply the equations of motion to calculate the braking distance.

V^{2} = U^{2}  + 2as; where V is the final velocity, U is the initial velocity, a is the acceleration and s is the displacement.

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7 0
3 years ago
Which word causes a change in motion
AnnZ [28]

<em>STOP </em>! often can if you shout it loud enough.

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8 0
3 years ago
Read 2 more answers
A spherical steel ball bearing has a diameter of 2.540 cm at 20.00°C. (Assume the coefficient of linear expansion for steel is 1
shusha [124]

Answer:

(a) 2.542 cm

(b) 272.7°C

Explanation:

diameter, d = 2.540 cm

T1 = 20°C

α = 11 x 10^-6 /°C

(a) Let d' be the diameter.

T2 = 87°C

Use he formula for the areal expansion

A' = A ( 1 + βΔT)

where, β is the coefficient of areal expansion and ΔT is teh rise in temperature, A' be the area at high temperature and A be the area at low temperature.

β = 2 α = 2 x 11 x 106-6 = 22 x 10^-6 /°C

So,

\frac{\pi D'^{2}}{4}=\frac{\pi D^{2}}{4}\left ( 1+\beta \Delta T \right )

D'^2 = 2.54^2 ( 1 + 22 x 10^-6 x 67)

D' = 2.542 cm

(b) Let the change in temperature is ΔT.

Use the formula for the volumetric expansion

ΔV = V x γ x ΔT

Where, γ = 3 x α = 3 x 11 x 10^-6 = 33 x 10^-6 /°C

0.9/100 = 33 x 10^-6 x ΔT

ΔT = 272.7°C

6 0
3 years ago
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