Answer:
4816N
Explanation:
Height = 3m
Mass = 70kg
g = 9.8m/s²
S = 50cm = 0.5m
The total force = the weight of the body + impact force.
Impact force = ma but a = v / t
Using equation of motion,
V² = u² + 2as
V² = u² + 2gh
But u = 0m/s (since the body is at rest)
V² = 0 + 2 * 9.8 * 3
V² = 58.8
V = √(58.8)
v = 7.668m/s ≈ 7.67m/s
The impact interval = ?
Average velocity = total distance / time taken
V = 2s / T
T = (2 * s) / v
T = (2 * 0.5) / 7.67
T = 1 / 7.67
T = 0.13 seconds
The total force F = (mg + ma)
But a = v / t
F = m(g + v / t )
F = 70 * [ 9.8 + (7.67/0.13)]
F = 70 * (9.8 + 59)
F = 4816N
Hello
When all the stages of scientist method being covered. After that, you can to modify any theory according to the observations, measures, etc.
Best regards
An electric current is an orderly, directed movement of electrically charged particles
Answer:
Question: What is the current in a 160V circuit if the resistance is 2Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 2Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 2
⇒ I = 160 / 2 = 80A
\rule{200}2
Question: What is the current in a 160V circuit if the resistance is 20Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 20Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 20
⇒ I = 160 / 20 = 8A
\rule{200}2
Question: What is the current in a 160V circuit if the resistance is 10Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 10Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 10
⇒ I = 160 / 10 = 16A
\rule{200}2
Question: Based on questions 2, 3, and 4, what happens to the current in a circuit as the resistance decreases? Increases?
Answer:
From ohms law
⇒ I = V / R
If we take Voltage as proportionality constant
⇒ I ∝ 1 / R
So, we can conclude that current is inversely proportional to resistance.
From 2, 3, 4 questions we can conclude that,
If resistance increases, current decreases and when resistance decreases, current increases.
\rule{200}2
Question: What voltage is required to move 6A through 5Ω?
Answer:
Resistance ( R ) = 5Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 5
⇒ V = 30V
\rule{200}2
Question: What voltage is required to move 6A through 10Ω?
Answer:
Resistance ( R ) = 10Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 10
⇒ V = 60V
\rule{200}2
Question:What voltage is required to move 6A through 20Ω?
Answer:
Resistance ( R ) = 20Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 20
⇒ V = 120V
\rule{200}2
Applying conservation of momentum
Quarterback mass = 80 kg
ball mass = 0.43 kg
Initially both together but horizontal velocity of both 0
initial momentum = 0
Final momentum = 15*0.43 - 80v
initial = final (law of conservation of momentum)
6.45 = 80v
v = 0.08 m/s