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Kruka [31]
2 years ago
9

5. Here are two copies of the same figure. Show two different ways for

Mathematics
1 answer:
dedylja [7]2 years ago
3 0

The two different ways of finding the area are,
Case 1 = assume horizontal rectangles,
Case 2 = assume vertical rectangles.

<h3>What is a rectangle?</h3>

the rectangle is a four-sided polygon whose opposites sides are equal and has an angle of 90° between its sides.

Here,

case 1,
As shown in the image
Area = sum of horizontal rectangles
Area = 10 * 3 + 2 * 5 + 2 * 1
Area  = 30 + 10 + 2
Area = 42    

Case II,
As shown in right figure,
Area of the vertical rectangles
Area = 3 * 5 + 5 * 3 + 2 * 6
Area = 15 + 15 + 12
Area = 42
Here, the area in case 1 is equal to case 2.

Thus, the two different ways of finding the area have shown above.

Learn more about rectangles here:
brainly.com/question/16021628

#SPJ1

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Answer:

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Step-by-step explanation:

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5 0
3 years ago
Find (fºg)(1)<br> f(x) = x² - 1<br> g(x) = √x <br> A.0<br> B.1<br> C.4 √2<br> D. √8
Savatey [412]

Given:

The function are

f(x)=x^2-1

g(x)=\sqrt{x}

To find:

The value of (f\circ g)(1).

Solution:

We have,

f(x)=x^2-1

g(x)=\sqrt{x}

We need to find the value of (f\circ g)(1).

(f\circ g)(1)=f(g(1))            [\because (f\circ g)(x)=f(g(x))]

(f\circ g)(1)=f(\sqrt{1})            [\because g(x)=\sqrt{x}]

(f\circ g)(1)=f(1)      

(f\circ g)(1)=(1)^2-1                  [\because f(x)=x^2-1]

(f\circ g)(1)=1-1      

(f\circ g)(1)=0      

The value of (f\circ g)(1) is 0.

Therefore, the correct option is A.

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3 years ago
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