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MAXImum [283]
1 year ago
11

Determine the poh of a 0. 188 m nh3 solution at 25°c. the kb of nh3 is 1. 76 × 10-5.

Chemistry
1 answer:
S_A_V [24]1 year ago
7 0

The pOH of the ammonia (NH₃) solution is 2.74.

Calculation:

We will start by composing a balanced ionization of NH₃ in aqueous.

NH₃(aq) + H₂O (l) → NH₄⁺(aq) + OH⁻(aq)

We'll also measure each compound's concentration at the end of the process.

NH₃ will partially dissociate. The quantity of NH3's dissociates can be disregarded. The concentration of NH₃ there at the final reaction is then nearly identical to that at the beginning reaction. NH₃ has a final concentration of 0.188 M.

NH₃≈ 0.188 M

As NH₄⁺ and OH ⁻ have the same ratio, then

[NH₄⁺]= [OH ⁻]

To determine the expression for the concentration of [OH] ions, we shall organize the accordance with the applicable (base constant) for the process into a written form.

Kb = ([NH₄][OH⁻]) / [NH₃]

Hence, the concentration of [NH₄⁺] can be written in the form of [OH⁻].

Kb = ([OH-] [OH⁻]) / [NH₃]

Kb = [OH⁻]² / [NH₃]

[OH⁻]² = Kb *[NH₃]

[OH⁻] = √(Kb *[NH₃])

Next, to find out the OH⁻ concentration we have to express the concentration as a form of the Kb equation :

[OH⁻] = √(1.76 * 10⁻⁵ * 0.188)

[OH⁻] = √3.31 * 10⁻⁶

[OH⁻] = √1.82 * 10⁻³

Hence,

pOH = -log[OH⁻]

pOH = - log1.82 * 10⁻³

pOH = 3 - log1.82

pOH = 2.74

So, the pOH of the NH₃ solution is 2.74.

Learn more about NH₃ here:

brainly.com/question/17021611

#SPJ4

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What is the molar mass of just the O in CO2?
Vlad1618 [11]

Answer:

16 g/mol

Explanation:

In CO2, it means we have 1 mole of carbon and 2 moles of oxygen.

However, we want to find the molar mass of just a single mole of oxygen.

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8 0
3 years ago
Solve
stiv31 [10]

The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the following Charle's law equation:

V1/T1 = V2/T2

Where;

  • T1 = initial temperature
  • T2 = final temperature
  • V1 = initial volume
  • V2 = final volume

  • V1 = 9L
  • V2 = ?
  • T1 = 325K
  • T2 = 450K

9/325 = V2/450

325V2 = 4050

V2 = 4050/325

V2 = 12.46L

Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

Learn more about volume at: brainly.com/question/2817451

7 0
2 years ago
The following data was collected when a reaction was performed experimentally in the laboratory.
Lera25 [3.4K]

Answer:

Mass = 279.23 g

Explanation:

Given data:

Number of moles of Fe₂O₃ = 3 mol

Number of moles of Al = 5 mol

Maximum amount of iron produced by reaction = ?

Solution:

Chemical equation:

Fe₂O₃ + 2Al    →     Al₂O₃  +  2Fe

Now we will compare the moles of iron with Al and iron oxide.

                          Fe₂O₃     :       Fe

                             1           :        2

                             3          :       2×3 = 6 mol

                            Al          :          Fe

                              2         :           2

                               5        :           5 mol

The number of moles of iron produced by Al are less so Al is limiting reacting and it will limit the amount of iron so maximum number of iron produced are 5 moles.

Mass of iron:

Mass = number of moles × molar mass

Mass =   5 mol  ×  55.845 g/mol

Mass = 279.23 g

 

3 0
2 years ago
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