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Scorpion4ik [409]
3 years ago
9

PLEASE HELPPPP How would life on earth be different if it axis were not tilted which respect to its orbit

Chemistry
2 answers:
olga2289 [7]3 years ago
5 0
The season would be much shorter
Licemer1 [7]3 years ago
4 0
Answer - D. The seasons would be much shorter
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Water can be formed in the following reaction: 2H2 + O2 —> 2H2O. If you have 12 moles of Hydrogen gas (H2), how many moles of
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How many atoms are in 4 moles of oxygen?
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There are 6.022 × 10 23 O atoms in a mole of O atoms. There are 6.022 × 10 23 O 2 molecules in a mole of . Since you have 2 oxygen atoms in one molecule, there are 2 × 6.022 × 10 23 O atoms in a mole of . A 'mole' is not short for a 'molecule

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Use Boyle's Law to explain what would happen to the volume of a helium- filled balloon if it was carried underwater by a diver t
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Expressed in scientific notation(6.0 x 104) (3.1 x 10-1) =
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A 12.0 g sample of a metal is heated to 90.0 ◦C. It is then dropped into 25.0 g of water. The temperature of the water rises fro
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Answer:

The specific heat of the metal is 0.34 J/g°C

Explanation:

Step 1: Data given

Mass of the metal = 12.0 grams

Mass of the water = 25.0 grams

Initial temperature of the metal = 90.0 °C

Initial temperature of the water = 22.5 °C

Final temperature = 25 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of the metal

Qlost = Qgained

Q = m*c*ΔT

Qmetal = -Qwater

m(metal) *c(metal)* ΔT(metal) = -m(water) * c(water) *ΔT(water)

⇒ with mass of metal = 12.0 grams

⇒ with c(metal) = TO BE DETERMINED

⇒ with ΔT(metal) = T2 - T1  = 25.0°C - 90.0 °C = -65.0 °C

⇒ with mass of water = 25.0 grams

⇒ with c(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.0 - 22.5 °C = 2.5 °C

12.0 * c(metal) * -65.0 °C = -25.0g * 4.184 J/g°C * 2.5°C

-780.0 * c(metal) = -2615  ( 2.6*10^3 with sig figs)

c(metal) = 0.335 (=0.34 with sig figs)

The specific heat of the metal is 0.34 J/g°C

3 0
2 years ago
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