_____ stars can be between 0.08 to 130 solar masses.

How many moles of calcium chloride would react with 5. 99 moles of aluminum oxide?

slega [8]

There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .

The balanced chemical equation between reaction between calcium chloride and aluminum oxide is given as,

$3CaCl_{2} (aq)+Al_{2} O_{3} (s)$ → $3CaO_{2} (s)+2Al Cl_{3} (aq)$

The molar ratio of above reaction is 3:1

It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.

The number of moles of calcium chloride requires to react with 5. 99 moles of aluminum oxide = 3 × 5. 99 = 17.97 moles

The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .

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How do you measure the volume of a rubber duck?

EleoNora [17]

Answer:

Im sorry i though this was a joke i don't know I'm sorry:

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Relate pH values of 9.1, 1.2, and 5.7 to hydronium and hydroxyl ion concentration.

trapecia [35]

Answer:

9.1 = basic 1.2= very acidic 5.7= acidic

Explanation:

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3 years ago

3.5g of a Certain compound X, known to be made of carbon, hydrogen, and perhaps oxygen, and to have a molecular molar mass of 15

shutvik [7]

Answer:

C₅H₁₀O₅

Explanation:

1. Calculate the mass of each element in 2.78 mg of X.

(a) Mass of C

$\text{Mass of C} = \text{5.13 g CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{1.400 g C}$

(b) Mass of H

$\text{Mass of H} = \text{2.10 g H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g H$_{2}$O}} = \text{0.2349 g H}$

(c) Mass of O

Mass of O = 3.5 - 1.400 - 0.2349 = 1.87 g

2. Calculate the moles of each element

$\text{Moles of C = 1400 mg C}\times\dfrac{\text{1 mmol C}}{\text{12.01 mg C }} = \text{116.6 mmol C}\\\\\text{Moles of H = 234.9 mg H} \times \dfrac{\text{1 mmol H}}{\text{1.008 mg H}} = \text{233.1 mmol H}\\\\\text{Moles of O = 1870 mg O} \times \dfrac{\text{1 mmol O}}{\text{16.00 mg O}} = \text{116 mmol O}$

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

$\text{C: } \dfrac{116.6}{116.6}= 1\\\\\text{H: } \dfrac{233.1}{116.6} = 1.999\\\\\text{O: } \dfrac{116}{116.6} = 1.00$

4. Round the ratios to the nearest integer

C:H:O = 1:2:1

5. Write the empirical formula

The empirical formula is CH₂O.

6. Calculate the molecular formula.

EF Mass = (12.01 + 2.016 + 16.00) u = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

$n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{150 u}}{\text{30.03 u}} = 5.00 \approx 5$

MF = (CH₂O)₅ = C₅H₁₀O₅

The molecular formula of X is C₅H₁₀O₅.

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Effect of fossil fuel emission on oceans?

BlackZzzverrR [31]

Fossil fuel emissions can create acid rain, which in turn increases the pH of ocean water, harming the organisms in the ocean.<span />

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