A contains 38.5 g of tin for each 12.3 g of fluorine:
<span>mole ratio: </span>
<span>(38.5 g)/(118.71 g/mol):(12.3 g)/(18.998 g/mol) = 0.324:0.647 = 1:2 ⇒ SnF₂ </span>
<span>B contains 56.5 g of tin for each 36.2 g of fluorine: </span>
<span>mole ratio: </span>
<span>(56.5 g)/(118.71 g/mol):(36.2 g)/(18.998 g/mol) = 0.476:1.905 = 1:4 ⇒ SnF₄
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Answer:
The statement is true.
Explanation:
Organisms can be unicellular (made up of one cell) or multicellular (consisting of more than one cell).
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In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.
<h3>What is molarity?</h3>
Molarity (M) is a unit of concentration of solutions, and it is defined as the moles of a solute per liters of a solution.
- Step 1: Calculate the liters of solution required.
A chemist has a 3.00 M KBr solution and wants to measure 0.733 moles of KBr. The required volume is:
0.733 mol × (1 L/3.00 mol) = 0.244 L
- Step 2: Convert 0.244 L to mL.
We will use the conversion factor 1 L = 1000 mL.
0.244 L × (1000 mL/1 L) = 244 mL
In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.
Learn more about molarity here: brainly.com/question/9118107
a) The change here is that metallic iron is converted into ions and copper is deposited. This is called a displacement reaction.
b) 
is oxidised in this reaction.
c)$ \mathrm{Fe_{(s)}+ CuSO_{4(aq)} \rightarrow FeSO_{4(aq)} + Cu_{(s)}}$
