Answer:
The explanations are given in the section below
Explanation:
First step:
We need to understand the acid-base equilibrium of the reaction. Bear in mind that the conjugate acid-base pairs are species that differ by one proton. Furthermore, one is a Lewis acid (meaning the ability to protons) and the conjugate base (accepts protons)
A simple conjugate base is obtained by removing one proton from an acid as shown below:
HX ⇄ A⁻ + H⁺
The diagrams are as follows:
Answer:
ithink it is c but i dont my ghess
Explanation:
i want to do thos for the points tbh
Answer:
#1 Exposition
#2 Background information
#3 Complication
this is right unless you're speaking of theme plot conflict climax falling action or conclusion
Answer:
Molarity = 0.95 mol/dm³
Explanation:
Given data:
Volume of H₂SO₄ = 15.8 cm³
Volume of NaOH = 20 cm³
Concentration of NaOH = 1.5 mol/dm³
Concentration of H₂SO₄ = ?
Solution:
Chemical equation:
NaOH + H₂SO₄ → Na₂SO₄ + H₂O
First of all we will calculate the number of moles of NaOH and for that we will convert the units first,
Volume = 20 cm³/1000 = 0.02 L
Concentration of NaOH = 1.5 mol/dm³
1 mol/dm³ = 1 mol/L
Concentration of NaOH = 1.5 mol/L
Number of moles of NaOH:
Molarity = number of moles / volume in L
1.5 M = number of moles / 0.02 L
Number of moles = 1.5 M ×0.02 L
Number of moles = 0.03 mol
Now we will compare the moles of NaOH and H₂SO₄
NaOH : H₂SO₄
2 : 1
0.03 : 1/2×0.03 = 0.015 mol
Concentration of H₂SO₄:
Volume of H₂SO₄:
15.8 cm³/1000 = 0.0158 L
Molarity = number of moles / volume in L
Molarity = 0.015 mol / 0.0158 L
Molarity = 0.95 mol/L
1 mol/L = 1 mol/dm³
Molarity = 0.95 mol/dm³
