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Dvinal [7]
2 years ago
13

A rocket is traveling toward the earth at 12c when it ejects a missile forward at 12c relative to the rocket.

Physics
1 answer:
Ahat [919]2 years ago
4 0

The correct value for the rocket speed measured by an observer on earth would be = 14c

<h3>Calculation and of the rocket speed</h3>

To calculate the speed of the rocket we should observe that the rocket and the missile are in a relative motion which are moving on the same direction.

The speed of the rocket = 12c

The speed of the missile = 12c

The individual speed of earth =0c

But, the relative speed of the missile and the Earth is the sum of individual speeds.

Thus, the speed of rocket as measured by an observer on the Earth would be 0 + 14c = 14c.

Therefore, the correct value for the rocket speed measured by an observer on earth would be =14c

Learn more about relative motion here:

brainly.com/question/17228388

#SPJ1

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Calculate the pressure of water in a will if the deep of the water is 10 m​
Bas_tet [7]

Answer:

98,000 pa

Explanation:

The formula for water pressure is as follows:

pressure = pgh

Where <em>p </em>is the density of water (in kg/m3), <em>g </em>is the gravitational field strength, and <em>h </em>is the height of the water.

The density of water is 1000kg/m3, the gravitational field strength is 9.8, and the height is 10. Substituting in these values:

pressure = 1000 \times 9.8 \times 10

pressure = 98000

7 0
2 years ago
Shadow is formed when an_____<br>object comes in the<br>way<br>of light.​
Zanzabum

Answer:

shadow is formed when an opaque object comes on path of light shadows are formed because light travels in a straight line and it can't pass through an opaque object

7 0
3 years ago
Read 2 more answers
A 0.1 kg toy contains a compressed spring. when the spring is released the toy fly 0.45 m upwards from ground level before falli
trapecia [35]

The speed of the toy when it hits the ground is 2.97 m/s.

The given parameters;

  • mass of the toy, m = 0.1 kg
  • the maximum height reached by the, h = 0.45 m

The speed of the toy before it hits the ground will be maximum. Apply the principle of conservation of mechanical energy to determine the maximum speed of the toy.

P.E = K.E

mgh_{max} = \frac{1}{2} mv_{max}^2\\\\gh_{max} = \frac{1}{2} v_{max}^2\\\\v_{max}^2= 2gh_{max}\\\\v_{max} = \sqrt{2gh_{max}}

Substitute the given values and solve the speed;

v_{max} = \sqrt{2\times 9.8 \times 0.45} \\\\v_{max} = 2.97 \ m/s

Thus, the speed of the toy when it hits the ground is 2.97 m/s.

Learn more here: brainly.com/question/7562874

7 0
3 years ago
A man has a mass of 110kg . what is his weight?
Alisiya [41]
<span>1078 kgm / s would be the answer I hope this helps!!!</span>
5 0
4 years ago
Read 2 more answers
Can someone check my answers and tell me if their correct?
Otrada [13]

Seven

The magnitude is pointing towards the origin and is at - 20 degrees. The combination makes 160 with the x axis: C answer

Eight

They keep doing this. They use distance where they should use displacement but they use distance to try and fool you. It's a mighty poor practice.

The distance between the start and end points is the displacement. That "distance" is 180*sqrt(25) = 900 . The actual distance should be 180*4 + 180*3 = 720 + 540 = 1260. That's what a car's odometer or a bicycle odometer would read.  the difference is 360.

I really do object to the wording, but what can I do?

Nine

Nine is the same thing as 8.

Displacement = sqrt(400^2 + 80^2)= sqrt(166400) = 408

The actual distance is 400 + 80 = 480

The difference is the answer = 480 - 408 = 72 <<<< Answer

Ten

This is just the displacement magnitude.

dis = sqrt(30^2 + 80^2)

dis = sqrt(900 + 6400)

dis = sqrt(7300)

dis = 85.44 <<<< Answer D

Twelve

Vi =  2.15*Sin(30) = 1.075 m/s

vf = 0

a = - 9.81

t = ?

<u>Formula</u>

a = (vf - vi)/t

<u>Solve</u>

-9.81 =  (0 - 1.075)/t

- 9.81 * t = -1.075

t = 0.11 seconds

Thirteen

I'm leaving this last one to you. You need the initial height xo to answer it properly. Judging by the other questions, this one is right.

Edit

That is a surprise! Really quickly

d = 3.2 m

a = - 9.82

vf = 0

vi = ?

vf^2 = vi^2 - 2*a*d

0 = vi^2 - 2*9.81*3.2

vi = sqrt(19.62*3.2)

vi = 8.0  m/s   But that is the vertical component of the speed

v = vi/sin(25)

v = 8.0/sin(25) = 11


6 0
3 years ago
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