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Andrews [41]
3 years ago
13

Which image shows the correct way of lining up vectors to add them together?​

Physics
1 answer:
Illusion [34]3 years ago
3 0

Answer:

D

Explanation:

I think is D because first is the line is going up and then makes a Straingt line

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A football is thrown at an angle of 30.° above the horizontal. The magnitude of the horizontal
VladimirAG [237]

Answer:

1.53 s

Explanation:

Initially vertical component of velocity of the ball, uy = 7.5 m/s

Net displacement is vertical direction is zero, Δy =0

Use second equation of motion:

Δy = uy t + 0.5 a t²

Here, acceleration a = -g                           (g =9.8 m/s²)

Substitute all the values and solve for g

0 = 7.5 t -0.5 (9.8)t²

7.5 t = 4.9 t²

t = 1.53 s

8 0
3 years ago
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If your boat weighs 1600 n, how much water will it displace when it’s floating motionless at the surface of a lake?
alexdok [17]
1000 kg water will be displace
5 0
3 years ago
ln the constellation of Orion, you can see a group of stars and other objects that appear in the shape of a sword. Ln the middle
bagirrra123 [75]

Answer:

Nebula

Explanation:

 Given that in the constellation of Orion, you can see a group of stars and other objects that appear in the shape of a sword. Ln the middle of the sword, a bright "fuzzy star" appears. Astronomers looking at this object through telescopes refer to it as a "stellar nursery." Another name for this object is called NEBULA.

The space where new stars are forming anew is known as nebulae

7 0
3 years ago
Please help meh its due
Fed [463]
-0.000393025 light years
3 0
2 years ago
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Several large firecrackers are inserted into the holes of a bowling ball, and the 6.3 kg ball is then launched into the air with
Anni [7]

Answer

given,

mass of the ball = 6.3 kg

speed of the ball = 10.4 m/s

angle made with horizontal = 43°

m_a = 1.8 kg               v_a = 2.2 m/s

m_b = 1.6 kg               v_b = 1.8 m/s

mass of third particle = 6.3 - 1.8 - 1.6

                                   = 2.9 kg

u cos θ = 10.4 x cos 43° = 7.61 m/s

by using conservation momentum along x-axis

6.3 x 7.61 = 1.8 × (-2.2) + 0 + 1.6 × V₃ₓ

V₃ₓ = 32.44 m/s (toward right)

by using conservation momentum along y-axis

0 = 0 + 1.6 x 1.8 + 1.6 × V₃y

V₃y = -1.8 m/s (indicate downward)

velocity of the third particle

v = \sqrt{32.44^2 + (-1.8)^2}

v = 32.49 m/s

tan \theta = \dfrac{-1.8}{32.44}

\theta = tan^{-1}(\dfrac{-1.8}{32.44})

θ = 3.176° (downward with horizontal)

4 0
3 years ago
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