get hold of some of her equipment, and throw it away from the craft. she should recoil to the craft ... and hope ???
Answer:
Option (A)
Explanation:
A flowchart can be described as a representation of a process or an algorithm in a sequential manner (stepwise) in the form of diagrams. These steps are made of symbols that are connected to one another with the help of arrows. These arrows are used to show the direction of the process.
There are mainly four symbols that are used to describe a flow chart, which includes-
- Oval or Pill Shape- This type of symbol is used to depict the start or the end of a process.
- Rectangle Shape- This type of symbols is used to describe the process
.
- Diamond Shape- This type of symbol is used to represent decision
s.
- Parallelogram- This type of symbol is used for the representation of an input or an output.
Thus, the correct answer is option (A).
Answer:
A.The positive z-direction
Explanation:
We are given that
Linear charge density of long line which is located on the x-axis=
Linear charge density of another long line which is located on the y-axis=
We have to find the direction of electric field at z=a on the positive z-axis if
and
are positive.
The direction of electric field at z=a on the positive z-axis is positive z-direction .
Because
and
are positive and the electric field is applied away from the positive charge.
Hence, option A is true.
A.The positive z-direction
Answer:
The second dart leaves the gun two times as faster than the first one.
Explanation:
Assuming no energy loss during the spring-dart energy transfer, we have by the conservation of energy principle

Given an arbitrary
and its double,
, launch velocities are

For a 50 kg person receives an absorbed dose of gamma radiation of 20 millirads, the total energy absorbed is mathematically given as
E=0.1457J
<h3>What is the total energy absorbed?</h3>
Generally, the equation for the total energy absorbed is mathematically given as
E=mass*gamma radiation
Therefore
E=50*20*19^{-3}
E=0.1457J
In conclusion, the total energy absorbed
E=0.1457J
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