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Scilla [17]
3 years ago
5

The driver of a car slams on the brakes, causing the car to slow down at a rate of

Physics
1 answer:
sdas [7]3 years ago
7 0

Answer:

A. The time taken for the car to stop is 3.14 secs

B. The initial velocity is 81.64 ft/s

Explanation:

Data obtained from the question include:

Acceleration (a) = 26ft/s2

Distance (s) = 256ft

Final velocity (V) = 0

Time (t) =?

Initial velocity (U) =?

A. Determination of the time taken for the car to stop.

Let us obtain an express for time (t)

Acceleration (a) = Velocity (V)/time(t)

a = V/t

Velocity (V) = distance (s) /time (t)

V = s/t

a = s/t^2

Cross multiply

a x t^2 = s

Divide both side by a

t^2 = s/a

Take the square root of both side

t = √(s/a)

Now we can obtain the time as follow

Acceleration (a) = 26ft/s2

Distance (s) = 256ft

Time (t) =..?

t = √(s/a)

t = √(256/26)

t = 3.14 secs

Therefore, the time taken for the car to stop is 3.14 secs

B. Determination of the initial speed of the car.

V = U + at

Final velocity (V) = 0

Deceleration (a) = –26ft/s2

Time (t) = 3.14 sec

Initial velocity (U) =.?

0 = U – 26x3.14

0 = U – 81.64

Collect like terms

U = 81.64 ft/s

Therefore, the initial velocity is 81.64 ft/s

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Anni [7]

The torque required for the cylinder is 76.99 N m.

What is torque?

Torque may be defined as the product of the force and the distance perpendicular to the force from the axis of rotation.

Calculation of the angular acceleration:

The first kinematic equation for the rotational motion is,

ω=ω₀+αt

where ω₀ is the initial angular velocity, ω is the final angular velocity, α is the angular acceleration and t is the time. Since the cylinder starts from the rest, its initial angular velocity is zero.

Here, ω=320 rev/min or ω=320*2π/60 rad/sec, ω₀=0 and t=8.00 sec. Put these values in the above equation and solve it to get the value of angular acceleration.

320*2π/60=0+α*8

α=320*2π/(8*60)

α=4.19 rad/s^2

Calculation of the torque:

The torque T is given by the formula,

T=Iα

where I is the moment of inertia.

For the cylinder, I=1/2*mr^2

where m is the mass of the cylinder and r is the radius of the cylinder.

So,

T=1/2*mr^2*α

Here m=75 kg, radius r is half of the diameter r=1.4/2=0.7 m, and α=4.19 rad/s^2. Using these values in the formula of torque.

T=1/2*(75)*(0.7)^2*4.19

T= 76.99 N m

Learn more about the torque.

brainly.com/question/16049994

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6 0
1 year ago
Your cousin has looked after you your whole life and you always looked up to him. Today he told you he sells drugs; " That's whe
tatuchka [14]

Answer:

Honestly, you should have a firm resolve not to go into drug peddling.

Politely tell him you are not interested in the business, that you are most concerned about your future and the career path you have chosen for yourself already.

He will definitely feel bad, but you can go on to advise him.

You can also advise him to stop and highlight the dangers of doing drugs.

Explanation:

There are a whole lot of disadvantages involved in the drug business,

in fact, the disadvantages out weights the advantages in the long run.

say if one is caught and sent to a life long sentence, or if one is caught up with the effect of the use of hard drugs and the health implication, to the extent that one looses his/her sanity, you see it won't make any sense anymore doing drugs in the long run. so friend you can advise you cousin to stop and thinker of good businesses that cold fetch him cool money, without the law chasing him, with that he can be a contributor to economic growth by paying his taxes too

3 0
3 years ago
In the author's opinion, why is attitude the most important fitness level factor to consider? (
Cerrena [4.2K]
That's up to you because you have to go through the book to see their expressions
5 0
3 years ago
A metal disk of radius 6.0 cm is mounted on a frictionless axle. Current can flow through the axle out along the disk, to a slid
Galina-37 [17]

Answer:

0.09 N

Explanation:

We are given that

Radius of disk,r=6 cm=\frac{6}{100}=0.06 m

1 m=100 cm

B=1 T

Current,I=3 A

We have to find the frictional force at the rim between the stationary electrical contact and the rotating rim.

dF=IBdr

dF=IBdr

\tau=rdF=IBrdr

\tau=\int_{0}^{R}IBr dr

\tau=IB(\frac{R^2}{2}

Torque due to friction

\tau=R\times F

Where friction force=F

R\times F=\frac{IBR^2}{2}

F=\frac{IBR}{2}

Substitute the values

F=\frac{3\times 1\times 0.06}{2}

F=0.09 N

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3 years ago
The efficiency of a machine increases as the temperature inside _____ relative to the temperature outside.
Archy [21]
The answer is increases
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