The correct choice is
B. Double-replacement reactions
in this type of reaction , two ionic compounds react and swaps their cations or anions giving two new compounds in the product. hence the double replacement reactions does not deal with the nucleus. all other terms like strong nuclear forces, radioactivity and nuclear decay deal with the nucleus.
Answer:
Explanation:
Here the total force at the horizontal components will be equal to the centripetal force on the car. So we will have:
(1)
- f(fr) is the friction force
- N is the normal force
Now, the sum of forces at the vertical direction is equal to 0.
(2)
Let's combine (1) and (2) to find f(fr)

I hope it helps you!
Answer:
6.72 m/s
Explanation:
recall that the equations of motion may be expressed as
v² = u² + 2as
where,
v = final velocity,
u = initial velocity = 0 m/s because it is stationary before it starts falling
a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)
s = distance traveled = 2.3m
in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.
v² = u² + 2as
v² = 0² + 2(9.81)(2.3)
v² = 45.126
v = √45.126
v = 6.72 m/s
Answer:

Explanation:
Given:
- Three identical charges q.
- Two charges on x - axis separated by distance a about origin
- One on y-axis
- All three charges are vertices
Find:
- Find an expression for the electric field at points on the y-axis above the uppermost charge.
- Show that the working reduces to point charge when y >> a.
Solution
- Take a variable distance y above the top most charge.
- Then compute the distance from charges on the axis to the variable distance y:

- Then compute the angle that Force makes with the y axis:
cos(Q) = sqrt(3)*a / 2*r
- The net force due to two charges on x-axis, the vertical components from these two charges are same and directed above:
F_1,2 = 2*F_x*cos(Q)
- The total net force would be:
F_net = F_1,2 + kq / y^2
- Hence,

- Now for the limit y >>a:

- Insert limit i.e a/y = 0

Hence the Electric Field is off a point charge of magnitude 3q.
Answer:
Your moving vehicle has kinetic energy; as you increase your vehicle's speed, your vehicle's kinetic energy increases. The greater your vehicle's kinetic energy, the greater the effort that will be required to stop the vehicle.
Explanation:
I hope this explained up above. Have a great dayyyy:)