Answer: d
Explanation: divide it by 4
1.06 is the <u>maximum</u> refractive index that the liquid may have for the light to be totally reflected.
Only when a light source passes from a denser to a rarer medium can it completely reflect.
When the angle of incidence surpasses a specific critical value, specular reflection occurs in the more highly refractive of the two mediums at their interface, and this reflection is known as total reflection.
sin
= μ
/ μ
From the diagram
Angle of incidence = 60°
sin60° ≥ sin
= μ
/μ
μ
≤ μ
sin60°
μ
≤ √1.5 × √3/2
= 1.06
Hence, the maximum index that the liquid may have for the light to be totally reflected is 1.06
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