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ZanzabumX [31]
2 years ago
9

The illustration below shows the graph of y as a function of x.

Mathematics
1 answer:
slavikrds [6]2 years ago
3 0

Answer:

  • parabola
  • y = -6
  • x=2 and x=6
  • Greatest value of y is y=2 and it occurs when x = 4
  • For x between x = 2 and x = 6, y > 0

Step-by-step explanation:

<u>Definition</u>

  • A parabola is a curve where any point is at an equal distance from:

               a fixed point (the focus ), and

               a fixed straight line (the directrix )

From the graph we can see that this is indeed so. We can even calculate the parabola equation from the given graph but since that is not required, I am not illustrating the steps here to do that

  • The y-intercept is the value of y where the parabola cuts the y axis and from the graph we see that this occurs at y = -6
  • The x-intercepts are the x-values where the parabola crosses the x-axis and we can see that this occurs at x = 2 and x = 6
  • The greatest value of y occurs at the vertex of the parabola and we see that the vertex is at (4,2) ie greatest value of y is at y = 2 and occurs at x=4
  • Between x =2 and x = 6 we see that the y values greater than 0 ie y > 0

(Note on last question: If you exclude these two points then y > 0 between x=2 and x=6.Specifically it is 0 at x =2 and x=6 and > 0. So if you include these two points then y ≥ 0.  I have taken it as excluding the two points, x = 2 and x =6)

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Can someone tell me if im right? PLEASE DONT JUST SAY YES if you don’t know
tia_tia [17]

Answer: You are incorrect, the slope is correct, but the actual y-intercept is 205 ft.

Then the equation is:

y = (-15 ft/min)*x + 205 ft

Step-by-step explanation:

Ok, let's solve this.

We know that water is drained from a reservoir, let's assume that we can model this situation with a linear relation:

y = a*x + b

Where x is time, y is the height of the water in the reservoir, a is the slope (in this case represents how much changes the height of the water in the reservoir in one unit of time) and b is the initial height of the water in the reservoir.

We know that for a line that passes through the points (x₁, y₁) and (x₂, y₂) the slope is:

a = (y₂ - y₁)/(x₂ - x₁)

For this particular case we know that after 2 minutes the height of the water is 175 ft, then we have the point (2 min, 175 ft)

and after 5 minutes (so 7 minutes in total), the height of the water is 100ft, then: (7 ft, 100ft)

Then the slope of this:

a = (100 ft - 175 ft)/(7 min - 2 min) = (-75ft/5min) = - 15 ft/min

Then our line is something like:

y = (-15ft/min)*x + b

To find the value of b, we can use the fact that when x = 2 min, y = 175 ft

So if we replace these two values in the equation we get:

175ft = (-15 ft/min)*2 min + b

175 ft = -30 ft + b

175 ft + 30 ft = b                  

(here is your problem, it seems like you subtracted instead of adding in this part)

205 ft = b

Then the equation is:

y = (-15 ft/min)*x + 205 ft

So you are incorrect (but only for a little bit), you computed wrong the y-intercept.

3 0
3 years ago
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kap26 [50]
Parallel=same slope
Y=mx+b
Sub in the slope and point to solve for b
2=-6(-1)+b
2=6+b
2-6=b
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The equation is y=-6x-4; the answer is B
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goblinko [34]

Answer:

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Step-by-step explanation:

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Substitute:

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