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Mars2501 [29]
3 years ago
12

Y is 1 less than 2 times X which order pair fits this rule​

Mathematics
1 answer:
Anni [7]3 years ago
3 0

Answer:

y < 2X - 1

y = 2X - 1

Step-by-step explanation:

Let's try to make an equation from the worded problem.

"is Less than " means <

2 times means 2 * X

= 2X

y < 2X - 1

y = 2X - 1

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How do you graph y=-1/3x
givi [52]

Step-by-step explanation:

it is negative so the slope must go downwards from left to right. since it is 1/3, for every 3 to the right, you go one down.

4 0
2 years ago
WILL GIVE BRAINLIEST IF CORRECT! I'm timed plz Help
lesantik [10]

Answer:

C. q Superscript 12

Step-by-step explanation:

q  \: Superscript \:  12 =  {q}^{12} =   { ({q}^{6})}^{2}  \\

4 0
3 years ago
Read 2 more answers
If 2k, 5k-1 and 6k+2 are the first 3 terms of an arithmetic sequence, find k and the 8th term​
Klio2033 [76]

Answer:

see explanation

Step-by-step explanation:

The common difference d of an arithmetic sequence is

d = a_{2} - a_{1} = a_{3} - a_{2}

Substitute in values and solve for k, that is

5k - 1 - 2k = 6k + 2 - (5k - 1)

3k - 1 = 6k + 2 - 5k + 1

3k - 1 = k + 3 ( subtract k from both sides )

2k - 1 = 3 ( add 1 to both sides )

2k = 4 ⇒ k = 2

--------------------------------------------------------

The n th term of an arithmetic sequence is

a_{n} = a_{1} + (n - 1)d

a_{1} = 2k = 2 × 2 = 4 and

d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5

Hence

a_{8} = 4 + (7 × 5) = 4 + 35 = 39

4 0
3 years ago
On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
Help pls explain or don’t just help
Nimfa-mama [501]

Answer:

2 meters, cuz shovels are usually pretty long

3 0
3 years ago
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