The general form of a linear equation is
y = mx + b
where m = slope and b = y-intercept
Here m = 2/7
To get to its perpendicular equation, first the slope should be negative reciprocal. So the perpendicular slope is m = -7/2
Given the point (-2,3), use the point-slope form equation, that is
y - y1 = m(x - x1)
Plug in
y - 3 = (-7/2)[x - (-2)]
y - 3 = (-7/2)x - 7
y = (-7/2)x - 7 + 3
y = (-7/2)x - 4
That is the equation required.
Answer:
The graph of f(x) is shifted k units to the right of the graph of g(x).
Step-by-step explanation:
Given the function and where k <0.
As, horizontal depends on the value of x and are when
g(x)=f(x+h) graph shifted to left.
g(x)=f(x-h) graph shifted to right.
Now, given
But here k is negative, when k is considered positive then f(x) becomes
⇒ The graph of f(x) is shifted k units to the right of the graph of g(x).
Correct option is B.
Answer:
500
Step-by-step explanation:
multiply all of them
