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stira [4]
2 years ago
7

If 123 ml of a 1. 1 m glucose solution is diluted to 500. 0 ml, what is the molarity of the diluted solution?

Chemistry
1 answer:
Ludmilka [50]2 years ago
6 0

The molarity of the diluted solution is 0.2706 M.

Given,

M₁ = 1.1 M

V₁ = 123 mL

V₂ = 500.0 mL

The dilution law formula is M₁V₁ = M₂V₂

1.1*123=M₂*500

M₂=0.2706 M

<h3 /><h3>Molarity </h3>

Molarity, a concentration unit used in chemistry, is determined by dividing the number of moles of a solute by the number of liters of solution. The phrase "molar concentration" (also known as "molarity," "amount concentration," or "substance concentration") refers to the amount of a substance per unit volume of solution and is used to describe the concentration of a chemical species, specifically a solute, in a solution. The most frequent measure of molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units. A solution with a concentration of 1 mol/L is referred to as 1 molar, or 1 M.

Learn more about Molarity here:

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There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is  4.50  ×  10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50  ×  10 ⁻⁴

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We will use the following expression.

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Step 4: Calculate the percent ionization of nitrous acid

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