Answer:
The answer to your question is 0.54M
Explanation:
Data
Final concentration = ?
Concentration 1 = 0.850 M
Volume 1 = 249 ml = 0.249 l
Concentration 2 = 0.420 M
Volume 2 = 0.667 M
Process
1.- Calculate the number of moles in both solutions
Number of moles 1 = Molarity 1 x Volume 1
= 0.850 x 0.249
= 0.212
Number of moles 2 = Molarity 2 x Volume 2
= 0.420 x 0.667
= 0.280
Total number of moles = 0.212 + 0.280
= 0.492
2.-Calculate the final volume
Final volume = Volume 1 + Volume 2
Final volume = 0.249 + 0.667
= 0.916 l
3.- Calculate Molarity
Molarity = 0.492 / 0.916
Molarity = 0.54
Answer:
<h2>Molarity = 7 mol / L</h2>
Explanation:
Since the mass of NaCl and it's volume has been given we can find the molarity by using the formula
<h3>
</h3>
where
C is the molarity
m is the mass
M is the molar mass
v is the volume
From the question
v = 0.5 L
m = 205 g
We must first find the molar mass and then substitute the values into the above formula
M( Na) = 23 , M( Cl) = 35.5
Molar mass of NaCl = 23 + 35.5 =
58.5 g/mol
So the molarity of NaCl is
C = 7.00854
We have the final answer as
<h3>Molarity = 7 mol / L</h3>
Hope this helps you
For the answer to the question above,
I am going to assume that MnO2 is a catalyst most likely breakdown of H2O2
H2O2----MnO2------> H2O + 1/2 O2
<span>in that case, B) is answered in the trump suit </span>
---
<span>edit: I need to have a plate account to see - which I don't </span>
is it something like
2H2O2 ---------------> 2H2O + O2
...............MnO2
<span>where MnO2 is underneath the arrow, in that case, it means it is a catalyst and production will DRASTICALLY decrease in production</span>
Answer:
156 g Br. Explanation: In order to figure out how many grams of bromine you get in that many grams of calcium bromide, CaBr2 , you must find ...
