1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
deff fn [24]
3 years ago
5

What’s the formula for Lead(II) chlorite?

Chemistry
1 answer:
elena-s [515]3 years ago
4 0

Answer:

Pb(ClO2)2

Explanation:

You might be interested in
A drop of water (H20) has a mass of 2.34 x 10e-2 grams. How many
creativ13 [48]

Answer:

2333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333

Explanation:

2x3=1000

3 0
3 years ago
How many molecules are present in 4.21 moles of HBr?​
salantis [7]

Answer:

The answer is

<h3>2.53 × 10²⁴ molecules</h3>

Explanation:

The number of molecules present can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 4.21 × 6.02 × 10²³

We have the final answer as

<h3>2.53 × 10²⁴ molecules</h3>

Hope this helps you

6 0
3 years ago
Gifblaar is a small South African shrub and one of the most poisonous plants known because it contains fluoroacetic acid (FCH2CO
PSYCHO15rus [73]

[H_{3}O^{+}] = 0.00770 M

The equilibrium equation representing the dissociation of FCH_{2}COOH

FCH_{2}COOH(aq) + H_{2}O (l)    FCH_{2}COO^{-}(aq)+ H_{3}O^{+}(aq)

Given [H_{3}O^{+}] = 0.00770 M

Let the initial concentration of acid be x and change y

So y = [H_{3}O^{+}] =[FCH_{2}COO^{-}] = 0.00770 M

pK_{a} = 2.59K_{a} = 10^{-2.59}   = 0.00257 M

K_{a} = \frac{(0.00770 M)(0.00770 M)}{x - 0.00770}

0.00257 = \frac{0.00005929}{x - 0.00770}

0.00257 x - 0.00001979 = 0.00005929

x = 0.031 M

Therefore, initial concentration of the weak acid is <u>0.031 M</u>

4 0
3 years ago
"You have a solution of glucose in water that has a concentration of 2.50 M and a volume of 0.442 liters. You dilute this soluti
taurus [48]

Answer:

0.737M

Explanation:

C1V1=C2V2

2.50 x 0.442 = C x 1.5

1.105 = C x 1.5

C = 1.105/1.5

C = 0.737M

7 0
3 years ago
Describe how you would prepare a supersaturated solution.
Anastasy [175]
To make a supersaturated solution<span>, make a saturated </span>solution<span> of sugar by adding 360 grams of sugar to 100 mL of water at 80 degrees Celsius. When the water cools back down to 25 degrees, that 360 grams of sugar will still be dissolved even though the water </span>should<span> only dissolve 210 grams of sugar.</span>
4 0
3 years ago
Read 2 more answers
Other questions:
  • Why do we use a double arrow in the dissociation equation for a weak acid answer?
    15·1 answer
  • All matter on earth contains energy
    10·1 answer
  • For each of the following units and concentration values, mention if they are parts per million (ppm), parts per billion (ppb) o
    6·1 answer
  • Lakes can disappear due to *
    7·1 answer
  • Which of the following is a example of an inherited behavior
    12·1 answer
  • Briefly discuss interpretations of your observations and results. Discuss how your observations illustrated LeChatelier's princi
    6·1 answer
  • What would the formula be for this model above?
    6·1 answer
  • HELP PLS (CHEMISTRY)
    11·1 answer
  • Would the ph at the equivalence point be acidic, basic, or neutral for each given titration?.
    6·1 answer
  • Explain how to calculate the number of grams in 5.50 x 1022 atoms.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!