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Klio2033 [76]
2 years ago
7

Which point is located on the x-axis?

Mathematics
2 answers:
gtnhenbr [62]2 years ago
4 0

Answer:

Any point where the y-coordinate is 0 will be located on the x-axis.

hope this helps! <3

Sholpan [36]2 years ago
4 0

Answer:

(Any x, 0)

kinda short

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PLZ I NEED THIS FAST
neonofarm [45]

Answer:

I believe the correct answer is A

Step-by-step explanation:

7 0
3 years ago
The weights of a large number of miniature poodles are approximately normally distributed with a mean of 8 kilograms and a stand
harina [27]

Answer and Step-by-step explanation:

Considering the table attached.

(a) over 9.5 kg;

μ = 8

σ = 0.9

z = 9.5 - 8/0.9 ≈ 1.67

P (Z > 1.67) = 0.5 - P(0<Z<1.67) = 0.5 - 0.4525 = 0.0475

(b) at most 8.6 kg;

z = 8.6-8/0.9 ≈ 0.67

P(Z < 0.67) = 0.5 + P(0<Z<0.67) = 0.5 + 0.2486 = 0.7486

(c) between 7.3 and 9.1 kg.

z₁ = 7.3-8/0.9 ≈ -0.78

z₂ = 9.1 - 8/0.9 ≈ 1.22

P(-0.78 < Z < 1.22) = P(0 < Z < 0.78) + P(0 < Z < 1.22) = 0.2823 + 0.3888 = 0.6711

3 0
3 years ago
If you have 12 circles an you shade in3/4 of them, how many circles do you shade?
aleksandrvk [35]
This is a formula if you need one. DON'T forget to cross-multiply

3/4 = x/12


4 0
3 years ago
Due in 10 min help! <br> Find t.
lys-0071 [83]

Given:

A right angle triangle with angles 45, 45, 90 degrees.

Hypotenuse of the triangle = 7\sqrt{2} mm

Base of the triangle = t

To find:

The value of t.

Solution:

In a right angle triangle,

\cos \theta=\dfrac{Base}{Hypotenuse}

Using this trigonometric ratio in the given triangle, we get

\cos (45^\circ)=\dfrac{t}{7\sqrt{2}}

\dfrac{1}{\sqrt{2}}=\dfrac{t}{7\sqrt{2}}

\dfrac{7\sqrt{2}}{\sqrt{2}}=t

7=t

Therefore, the value of t is 7 millimetres.

8 0
3 years ago
Help me with this question
kaheart [24]
First combine like terms and put the expression in standard form. This expression is now in simplest form and cannot be simplified anymore.
3a + 10ab - 7a^2b - 10ab^2 + 12ab - (-4) + (-a^2b) - 5a
-10ab^2 - 8a^2b -2a + 24ab - (-4)

Hope this helps

5 0
4 years ago
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